Express the surface area of the surface obtained by rotating the graph of y = 3 sin (x) for 0 < x < as an integral (but do not evaluate). Choose the correct integral. / V1 +9cos² (x) dx 2n 3 sin x/1 + 9 cos? (x) dx 2л 3 sin x(1 + 3 cos (x) dx x/3 V1 +9 cos° (x) dx a/3 2л 3 sin x/1 +9 cos² (x) dx

Intermediate Algebra
10th Edition
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter8: Conic Sections
Section8.2: More Parabolas And Some Circles
Problem 63.2PS: By expanding (xh)2+(yk)2=r2, we obtain x22hx+h22ky+k2r2=0. When we compare this result to the form...
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Express the surface area of the surface obtained by rotating the graph of y = 3 sin (x) for 0 < x s
3
as an integral (but do
not evaluate).
Choose the correct integral.
n/3
V1 +9 cos? (x) dx
2n
x/3
3
sin x/1 +9 cos² (x) dx
O 2 *
x/3
3 sin x (1 + 3 cos (x)) dx
a/3
1 + 9 cos² (x) dx
R/3
2n
3 sin x/1 +9 cos (x) dx
Transcribed Image Text:Express the surface area of the surface obtained by rotating the graph of y = 3 sin (x) for 0 < x s 3 as an integral (but do not evaluate). Choose the correct integral. n/3 V1 +9 cos? (x) dx 2n x/3 3 sin x/1 +9 cos² (x) dx O 2 * x/3 3 sin x (1 + 3 cos (x)) dx a/3 1 + 9 cos² (x) dx R/3 2n 3 sin x/1 +9 cos (x) dx
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