Express the surface area of the surface obtained by rotating the graph of y = 5 sin (x) for not evaluate). Choose the correct integral. 5 [0²: π/3 2π = √1 + 25 cos² (x) dx π/6 π/3 = [² π/6 2π sin x 1 + 25 cos² (x) dx 2π π/3 π/3 5 sin x√1 + 25 cos² (x) dx 1 + 25 cos² (x) dx 5 sin x (1 + 5 cos (x)) dx 76 < x < π as an integral (but do

Calculus: Early Transcendentals
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Author:James Stewart
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Express the surface area of the surface obtained by rotating the graph of y = 5 sin (x) for
not evaluate).
Choose the correct integral.
5 [0²:
π/3
2π
= √1 + 25 cos² (x) dx
π/6
π/3
= [²
π/6
2π
sin x 1 + 25 cos² (x) dx
2π
π/3
π/3
5 sin x√1 + 25 cos² (x) dx
1 + 25 cos² (x) dx
5 sin x (1 + 5 cos (x)) dx
76
< x <
π
as an integral (but do
Transcribed Image Text:Express the surface area of the surface obtained by rotating the graph of y = 5 sin (x) for not evaluate). Choose the correct integral. 5 [0²: π/3 2π = √1 + 25 cos² (x) dx π/6 π/3 = [² π/6 2π sin x 1 + 25 cos² (x) dx 2π π/3 π/3 5 sin x√1 + 25 cos² (x) dx 1 + 25 cos² (x) dx 5 sin x (1 + 5 cos (x)) dx 76 < x < π as an integral (but do
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