f(3) = lim f(x)= x-3 f(5) lim f(x)= x-5 lim f(x)= lim f(x)= x-3° lim f(x) = x-5 lim f(x)= 1-5 M lim f(x)= lim f(x)= f(5) = lim f(x) = f(3) = lim f(x) = X-3 x-5 x-5° lim f(x)= lim f(x)=
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- [3 - x x 2 let fx)=+1 a) Find lim fx) and lim f) X-2 X-2+ exist? why? Sx) b) Dose lim X2a) lim f(x) x→0^- b) lim f(x) x→0^+ c) lim f(x) x→0 d) lim f(x) x→2^- e) lim f(x)…1. lim x → − 5 + F ( x ) 2. lim x → − 2 − F ( x ) 3. lim x → − 2 + F ( x ) 4. lim x → − 2 F ( x ) 5. lim x → 0 − F ( x ) 6. lim x → 0 + F ( x ) 7. lim x → 0 F ( x ) 8. lim x → 2 − F ( x ) 9. lim x → 2 + F ( x ) 10. lim x → 2 F ( x )
- \lim_{x\rightarrow 7}\frac{x^2-5x-24}{x^2-4x-32}x→7limx2−4x−32x2−5x−243. Evaluate lim x→5 √x+4-3/ x-5. Show your complete solution. 4. Evaluate lim x→1 x-1/ √x-1. Show your complete solution. 5. Prove that lim t→-2 √1-t3/t +3/2 / t+2= 1/4. Show your complete solution.(i) Lim x→∞ 5x-3 − 4 / 2x-2 + 9 (ii) Lim x→∞ (x - 3)2 / x2/2 - 2x -3