Factor the trinomial (but not completely) n^2+9n-52
We have
n2 +9n -52
Rewrite the above term, we get
n2 +13n - 4n -52
Taking n as a common in first two term and 4 as a common in last two term, we get
n( n + 13) -4 ( n + 13)
Now taking n + 13 as a common term, ...
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