Using user-defined functions with Python."Federal law requires that hourly employees be paid "time-and-a-half" for work in excess of 40 hours in a week. For example, if a person's hourly wage is \$12 and he or she works 60 hours in a week, the person's gross pay should be (40*12) + (1.5*12*(60-40)) = \$840 else it is (40*12) = \$480.Write a program that determine a person's weekly pay based on the calculation describe above. The main function should call three functions - one (multi-valued) for input, one to calculate the values, and one for output the person's gross pay."The attached screenshot is my code at the moment. I'm just stuck getting around this error. Thank you! def main():wage()calculate_earnings()gross_pay_finaldef wage():wage_per_hourfloat(input('\nEnter hourly wage: '))=hours_workedfloat(input('Enter Number of hours worked: '))def calculate_earnings(hours_worked):if hours_worked > 40:pay_gross =(40 * wage_per_hour) + (1.5 * wage_per_hour * (hours_worked - 40))else:pay_gross =(hours_worked *wage_per_hour)def gross_pay_final(pay_gross):print('Gross pay for week is ${:.2f}\n'.format(pay_gross))main()Enter hourly wage: 12.50Enter Number of hours worked: 47NameErrorTraceback (most recent call last) in ()17print('Gross pay for week is ${:.2f}\n'.format(pay_gross))18---> 19 main()1 frames in calculate_earnings()8 def calculate_earnings():wage()if hours_worked > 40:---> 1011pay_gross(40 *wage_per_hour) + (1.5 * wage_per_hour * (hours_worked40))12else:NameError: name 'hours_worked' is not definedSEARCH STACK OVERFLOW

Here, you are calling the functions but they needs parameters while calling or simply ignore the…

Answered: "Federal law requires that hourly…

Database System Concepts

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Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

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Using user-defined functions with Python.

"Federal law requires that hourly employees be paid "time-and-a-half" for work in excess of 40 hours in a week. For example, if a person's hourly wage is \$12 and he or she works 60 hours in a week, the person's gross pay should be (40*12) + (1.5*12*(60-40)) = \$840 else it is (40*12) = \$480.

Write a program that determine a person's weekly pay based on the calculation describe above. The main function should call three functions - one (multi-valued) for input, one to calculate the values, and one for output the person's gross pay."

The attached screenshot is my code at the moment. I'm just stuck getting around this error. Thank you!

def main():
wage()
calculate_earnings()
gross_pay_final
def wage():
wage_per_hour
float(input('\nEnter hourly wage: '))
=
hours_worked
float(input('Enter Number of hours worked: '))
def calculate_earnings(hours_worked):
if hours_worked > 40:
pay_gross =
(40 * wage_per_hour) + (1.5 * wage_per_hour * (hours_worked - 40))
else:
pay_gross =
(hours_worked *
wage_per_hour)
def gross_pay_final(pay_gross):
print('Gross pay for week is ${:.2f}\n'.format(pay_gross))
main()
Enter hourly wage: 12.50
Enter Number of hours worked: 47
NameError
Traceback (most recent call last)
<ipython-input-7-2c8feff658b4> in <module>()
17
print('Gross pay for week is ${:.2f}\n'.format(pay_gross))
18
---> 19 main()
1 frames
<ipython-input-7-2c8feff658b4> in calculate_earnings()
8 def calculate_earnings():
wage()
if hours_worked > 40:
---> 10
11
pay_gross
(40 *
wage_per_hour) + (1.5 * wage_per_hour * (hours_worked
40))
12
else:
NameError: name 'hours_worked' is not defined
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