Fieldwork No. 6 - Differential Leveling O FieldworksDue October 20, 2021 6:00 PMCloses October 23, 2021 12:00 PMInstructionsFIELDWORK DATA:Elevation at BMa = 175.00 m1.) Backsights:BMa = 1.81 mTP1 = 1.98 m%3DTP2 = 2.06 mTP3 = 1.77 mTP4 = 1.89 mTP5 = 1.56 mTP6 = 1.48 mTP7 = 1.13 mTP8 = 1.63 m%3DTP9 = 1.95 mTP10 = 2.00 m%3D2.) Foresights:TP1 =1.51 mTP2 = 1.16 mTP3 = 1.58 mTP4 = 1.42 mTP5 = 1.54 m||TP6 = 1.51 mTP7 = 1.71 mTP8 = 1.32 mTP9 = 1.40 mTP10 = 1.23 mBMb = 1.18 m%3D

Height of instrument = R.L/B.M + B.S R.L of any point = H.I - F.S...

Answered: Fieldwork No. 6 - Differential Leveling…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Complete the following level notes. Show your detailed solution and checking. Differential Leveling Station BS HI FS Elevation BM1 1.050 ---- 147.630 TP1 1.224 1.923 TP2 1.276 1.481 TP3 1.087 2.290 TP4 1.162 2.140 TP5 1.751 2.700 BM2 ---- 2.565
Differential leveling was performed to run the elevation of BM 3-1 located 30.00 meters to the right of station 3 + 480, to BM 3-2 located 27.50 m to the left of station 3 + 920.00. Calculate the elevations of the points and verify the quality of the annotations in the level book. STATION BS HI FS ELEVATION (m) BM 3-1 1.458 328.954 TP - 1 2.256 2.314 TP - 2 1.382 3.127 TP - 3 3.456 2.171 TP - 4 0.759 1.282 BM 3-2 2.000
Discuss with relevant examples any three applications of leveling.
The following consecutive reading were taken with a level and 4m leveling staff ground at common interval of 30m as 0.725 on A,0.935,2.845,3.745,3.935,0.965,1.135,1.785,2.625,3.845,0.965,1.575 and 2.015 on B. The elevation of point A is 220.50m. Makeup level book page, apply usual check and calculate the reduced levels of points. Also calculate the gradient of line AB.
Surveying Question: A differential leveling circuit starts at benchmark Concrete Benchmark (Elevation=232.051m) goes out to an unknown benchmark and then continues to a known control point (Elevation=227.975m). Two turning points are used with the measurements included in the attached table. Determine the elevation of the unknown benchmark Determine the order and class of the survey. For First order Class 1: Allowable Error= +/- 4(K)1/2 Range of Constant= m less than/equal to 4 For First Order Class 2: Allowable error= +/- 5(K)1/2 Range of constant= m greater than/equal to 4, and m less than equal to 5 (between 4 and 5) For Second Order Class 1: Allowable error = +/- 6(K)1/2 Range of Constant = m greater than/equal to 5, and m less than equal to 6 (between 5 and 6) For Second Order Class 2: Allowable error = +/- 8(K)1/2 Range of Constant = m greater than/equal to 6, and m less than equal to 8 (between 6 and 8) For Third Order, Any Class: Allowable Error = +/-12(K)1/2 Range…
Compute for HD if the upper, middle and lower hair readings in a three-wire levelling are 2.79m, 2.42m, and 2.06m respectively. Assume standard or usual values of K and C.
The following readings were successively taken in levelling work 2.230, 1.605, 0.990, 2.090, 2.865 level instrument was shifted after 3rd reading. If R.L of first station 100.000 m, the R.L of other stations will be Option 1: 100.625, 101.240, 100.140 Option 2: 101.605, 100.990, 102.090, 100.865 Option 3: 100.230, 100.625, 101.240, 100.465 Option 4: 100.625, 101.240, 100.465
Figure 3 shows staff readings obtained from a survey along the centerline of the road.The levelling commenced on TBM1 (23.832 m AOD) to TBM2 (24.082 m AOD) andthe reading were taken at 25 m intervals along the line. Calculate the reduce level ofall the chainage points. Apply the arithmetic checking.
The following consecutive readings were taken with a level and a 4mt. leveling staff on acontinuously sloping ground at common intervals of 30 m:0.855(onA),1.545,2.335,3.115,3.825,0.455,1.380,2.055,2.855,3.455,0.585,1.015,1.850,2.755,3.845(on B)Enter the readings on a level field book and work out the staff readings on that, Find theR.L of different points using Collimation Plane Method. RL of the BM is 200.000m.Calculate the slope of the ground.
A differential leveling loop began and closed on BM Tree (elevation 323.48 ft). The plus sight and minus sight distances were kept approximately equal. Readings (in feet) listed in the order taken are 3.18 1 +S2 on BM Tree, 4.76 1 -S2, and 2.44 1 +S2 on TP1, 3.05 1 -S2 and 6.63 1 +S2 on BM X, 3.64 1 -S2 and 2.35 1 +S2 on TP2, and 3.07 1 -S2 on BM Tree. Prepare, check, and adjust the notes.
plz, solve this question, it is not graded question It is Surveying-2 Regno : 5395
Following staff reading were taken with a level. The instrument having been shifted after the 4th, 7th and 10th reading. R.L. of the starting B.M. is 100.00m. Enter the reading in the form of a level book page. Find the R.L.of stations and apply usual checks. 2.665,3.745,3.830,2.275,2.645,0.385,0.960,1.640,2.845,3.845,2.680,and 3.265.

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