Fill in the blanks to solve the equation: 2k – 3 (4 – k) = 3k + 4 %3D | 2k 12+ = 3k + 4 - %3D -12 = 3k + 4 %3D -12 = 4 2k = %3D

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter5: Factoring Polynomials
Section5.13: Using Factoring To Solve Problems
Problem 12P
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Question
Fill in the blanks to solve the equation:
2k – 3 (4– k) = 3k + 4
2k 12+
= 3k + 4
-12 = 3k + 4
-12 = 4
2k =
k =
Question 2
Check your answer from question 1 using substitution. Be sure to show all your work.
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Transcribed Image Text:Fill in the blanks to solve the equation: 2k – 3 (4– k) = 3k + 4 2k 12+ = 3k + 4 -12 = 3k + 4 -12 = 4 2k = k = Question 2 Check your answer from question 1 using substitution. Be sure to show all your work. Edit View Insert Format Tools Table 12pt v Paragraph v B
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