Find a root of an equation f(x)=2x3-2x-5 using Newton Raphson method

Q: Use Newton’s method to find an approximate solution of 3 - x = ln x. Start with x0 = 2 and find x2.

A: Given: 3 - x = ln x That is  f(x)=3 - x - ln x Initial value x0 = 2.

Q: Let ƒ(x) = x4 - x3. Show that the equation ƒ(x) = 75 has a solution in the interval [3, 4] and use…

A:

Q: Find a real root of the equation x^4-x-10=0, using Newton-Raphson method correct to four decimal…

A: We have the equation x4-x-10=0 Now, we need to use the Newton-Raphson method to find the root. By…

Q: 2x и"(х) — и

A:

Q: f(x)=x3-7x²+8x-3 iF Xo =5

A: Using Newton-Raphson Method we determine the approximation to the solution, where  f(x)=…

Q: Q2: Find a root of x - 0.5 – 2-2x = 0 by using Newton-Raphson method correct to 4 decimals so that…

A: Solution :-

Q: By fixed-Point Iteration, evaluate f(x) =x² -x- e*starting at x1 = 0.

A: The given function is fx=x2-x-e-x To find: the root of the equation.

Q: The equation x5 + x4 − 5 = 0 has one real solution. Approximate it by Newton’s Method.

A: This is a problem of Newton Raphson method.

Q: Use Newton’s method to estimate the one real solution ofx3 + 3x + 1 = 0. Start with x0 = 0 and then…

A: x3+3x+1=0

Q: find a real root of the equation xe^x-2=0 using Newton's method

A: Explanation of the solution is given below...

Q: Find the root of the equation correct to 5 decimal places, using Newton-Raphson method with initial…

A:

Q: Calculate one of the roots of the equation f(x) = x ^ 3 + x ^ 2 - 2x - 4 = 0 with an error less than…

A:

Q: Determine the real root of f(x)=5x3-2x2+3x-1. Iterate until the estimated error falls equal to or…

A: Given that:f(x)=5x3-2x2+3x-1

Q: Use Newton - Raphson method with value of x0 = 0.2 to find the real root for the function: f(x) =…

A:

Q: Find the explicit solution of the separable equation

A:

Q: 2. Use Newton-Raphson Method to find the root of x'-2x²-5 = 0 between [1, 4] accurate to five…

A:

Q: Find the root of equation by usung the newton raphson methode f(x) = 0.48x³ -2.7x-5.36

A:

Q: Use the Newton's Method to solve the equation x + In x = 2. %3D

A:

Q: Use Newton's Method to approximate the zero(s) of the function f(x) = x' +4x +1

A: f(x) = x5 + 4x + 1 Basic formula for Newton's Method is: xn+1 = xn - fxnf'xn f'x = 5x4 + 41 + 0 =…

Q: use Newton-Raphson method to obtain a root of equation x'-5x+3=0

A:

Q: Find root √80 using Newton Raphson method.

A:

Q: Use the Newton-Raphson method to find an approximate solution of the equatione-5x = xin the interval…

A: Let f(x) be defined as e-5x – x. In that case, we have to find the solution of the equation f(x) = 0…

Q: use the Newton's Method to solve the equation x+lnx=2

A:

Q: I Pind the root of the function byusing Newton- Raphson method) with Xo1,where fcx> = x²_5x +6

A: Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: Use Newton's method to approximate a root of the equation 3x^3+5x+2=0 as follows. Let x1=-1 be the…

A:

Q: 2. Apply Newton's Method to determine a real root of the equation f(x)=2x+24x+61x²-16x+1=0, for…

A:

Q: Find the approximate root of function f (x) = 0.48x³ - 2.7x - 5.36 by using the newton raphson…

A: Given function fx=0.48x3-2.7x-5.36             ……………………1 Initial guess x0=3.5

Q: Use Newton's Method with the function f(x) = x² – 2 and initial value xo = 1 to calculatex1,X2, X3 .…

A:

Q: 3. Solve xex- 3 = 0, correct to three decimal places by using the Newton- Raphson method.

A: Here, fx=xex-3⇒f'x=xex+ex f1=1*e1-3=-0.2817<0 f2=2*e2-3=11.778>0 Thus root lies between 1 and…

Q: Use Newton's method to estimate the one real solution of x + 5x +2 = 0. Start with x, = 0 and then…

A: here we have to find the roots of the given equation by using newton's method.

Q: f(x) = xe-* хе – sin²x

A:

Q: Use Newton-Raphson method to obtain a real root, correct to three decimal places, of the equation:…

A: To solve the following problem we use the formula of Newton Raphson Method  Xn+1 =  xn - fxnf'xn

Q: Use Fixed-point iteration or Newton-Raphson method to find the required root. Find the positive root…

A:

Q: Find the homogenous linear equation with real, constant coefficients that is satisfied by:…

A: Given that  Required differential equation is satisfied by   y= 6 + 3xe^x - cos x

Q: The Newton-Raphson method is used to find the roots of the equation: Ax) = x – cosTX ; Osxs1 If the…

A:

Q: Find a root of an equation f(x) = 2x3 - 2x - 5 using Newton Raphson method %3D

A:

Q: (2) where f(x)= x3-2x²-5

A:

Q: Use Newton's method to approximate a root of the equation 5x³ + 2x + 2 = 0 as follows. Let x1 = -1…

A: Newton’s Method: If xn is an approximation a solution of f(x)=0 and if f′(xn)≠0, then the next…

Q: Find one of the roots of the function using Regula-Falsi method. £ (x) = x- V+1

A:

Q: Use Newton's method to approximate a root of the equation x³ + x + 3 = 0 as follows. Let 1 1 be the…

A:

Q: Use Newton's method to find solutions of the non-linear equation for five iterations. Show working…

A: Here we will apply the process of Newton's method

Q: A quadratic equation x--4x+43D0 is defined with an initial guess of 10 and 20. Find the approximated…

A:

Q: use newton's method with the initial approximation x1=3 to find the second approximation of the…

A: We consider a function  f(x)=x2-10 It has zero = sqrt(10) We will use the Newton's method on it. We…

Q: Use Newton's method to estimate the smallest positive root of f(x)=-xr+2x² -5x+1.

A:

Q: Use the Newton-Raphson method to find an approximate solution of the equatione-7x = xin the interval…

A: The function

Q: Use Newton's method with the specified initial approximation x1 to find x3, the third approximation…

A:

Q: Use Newton Raphson Method to obtain a real root of x^3-5x+1=0 with x₀=0 until absolute error

A:

Q: Find the positive real root of x³ - x - 3 = 0 using Newton-Raphson method. If the starting guess…

A:

Q: Find a root of the x^4-27=0 equation using the Newton Raphson method (in 4 steps)

A: The given equation is x4-27=0. Let fx=x4-27. Then, f'x=4x3 Here, f2=24-27=16-27=-11<0…