Question
Asked Dec 8, 2019
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Find a unit vector normal to the plane containing
u = 31 - 2j - k and v = - 3i - 2j + 2k.
A unit vector normal to the plane containing u and v is ai + bj + ck where
b =
and c=
(Simplify your answers, including any radicals. Use integers or fractions for any numbers in the expression.)
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Find a unit vector normal to the plane containing u = 31 - 2j - k and v = - 3i - 2j + 2k. A unit vector normal to the plane containing u and v is ai + bj + ck where b = and c= (Simplify your answers, including any radicals. Use integers or fractions for any numbers in the expression.)

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Expert Answer

Step 1

Given, the plane containing the vectors

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и %3 3і— 2j -k and v %3D-3i — 2j + 2k

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Step 2

Now the unit normal (perpendicular) vector to the given pl...

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k i Let w = uxv=| 3 -1 -2 2 |-3 -2 Expanding the determinant along first row , we get w =i(-4-2)- j(6– 3)+ k(-6–6)=-6i– 3 j–12k .. normal vector to the plane is w=-6i – 3 j –12k

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Math

Trigonometry