Question

Asked Feb 29, 2020

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Find an equation of the tangent line at the given point.

(x + 2)^{2} − 6(2y + 3)^{2} = 3, (1,−1)

Step 1

Consider

(x + 2)^{2} − 6(2y + 3)^{2} = 3, (1,−1)

Step 2

Find the slope of the equation using implicit differentiation

Step 3

Find the slope at the point (1,−1)

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