Find an equation of the tangent line to the curve at the given point. Illustrate by graphing the curve and the tangent line on the same screen. y = x + Vx, (1,2) y = 3x? – x', (1, 2)

Q: y=(2x−1)' (2-3x)* at the point (1,1)

A: We have to determine the equation of the tangent line to the curve  y=2x-13 2-3x4, at the point 1,…

Q: consider the curve given by the equation x^3 - 2xy + y^3 = 0. Find the tangent line of this curve at…

A: Given equation is x3-2xy+y3=0..........(1) we have to find the tangent line of this curve at (1,1)

Q: Find an equation of the tangent line to the curve at the given point. y = 4x – 3x, (2, –4)

A: Given, y=4x-3x2Point=2, -4

Q: Find the equation of the tangent line to the curve at the given point.   y =?

A: The objective is to find the equation of the tangent line to the curve at the given point.

Q: Find the equation of the tangent line to the curve at (2, 1): x^2 + 4xy + y^2 = 13

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Q: Find an equation of the tangent line to the graph of the equation  x + y − ex − y = 3 at the point…

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Q: Find an equation of the tangent line and normal line to the curve at the given point. y = (2x)/(x2 +…

A: Given :          y=2xx2+1     1,1

Q: Find an equation of the tangent line to the curve at the given point. y = (1 + 5x)°, (0, 1) %|

A: Given equation of curve: Point (0, 1)

Q: Find the equation of the tangent line to the curve: y? – x³ = 1 at point (2, -3) %3D

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Q: Find an equation of the tangent line to the curve at the given point. y = 3x3 – x2 + 2, (2, 22) y =

A: Given curve and points are: y=3x3-x2+2  , 2,22

Q: Find an equation of the tangent line to the curve at the given point. y =  4x x + 3 ,…

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Q: Find the equation of the tangent line to the curve y- (1+2x) at the point (1,9)

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Q: Find the equation of the tangent line at the given value of x on the curve. y + xy? - 5 =x+3y; x= 3…

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Q: Find an equation of the tangent line to the curve at the given point. = sec X, (π/3, 2) y

A: The answer posted in the image would have been correct if the student had typed 23x instead of 23x…

Q: Find an equation of the tangent line to the given curve at the specified point. x² – 1 y = x² + x +…

A: We are going to find the tangent line equation to the given curve at the point (1,0) using an…

Q: 3) Find the equation of the tangent line to the curve the point (1, 1). y²(2 – x) = x³ at

A: Given curve is : y2(2-x) = x3

Q: Is there a formula to do this? What is the process?

A: Given curve is: First, find the slope of tangent line:

Q: Find an equation of the tangent line to the curve at a given point . y = x^4+ 5x^2 -x , (1, 7)

A: We have given a curve y.  We have to find the equation of the tangent line to the curve at point (1,…

Q: Find the equation of the tangent line to the curve y= (x-3)°(x+2) at the point (4,36).

A: Given,  The curve   y = x-38x+22   We have to find the equation of the tangent line to the curve at…

Q: Find the equation of the tangent line to the curve at the given point. y = /2x + 1, (4, 3) y =

A: See the attachment

Q: Find an equation of the tangent line to the curve at the given point. y = (1 + 3x)°, (0, 1)

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Q: Find an equation of the tangent line to the curve at the given point. y = 9e* + x, (0, 9) y =

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Q: ...... Find an equation of the tangent line to the curve at the given point. y = x + (3, 4)

A: This question is based on application of Derivative.

Q: Find the equation of the tangent line to the curve at the given point. y = /2x +1, (4, 3)

A: To find the slope, we find dy/dx at (4, 3) At (4, 3):

Q: Find the equation of the tangent line to the curve y=4+e2sinx at the point (0,5).

A: our objective is to find the tangent line equation.

Q: Find an equation of the tangent line to the curve at the given point. y = Vx, (25, 5)

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Q: Find an equation of the tangent line to the curve at the given point y = x³ – 3x + 1, (2,3)

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Q: Find an equation of the tangent line to the curve at the given point. y = x + (5, 6) y =

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Q: Find the equation of the tangent line to the curve at the given point. y = 4x^2-x^3, (1,3)

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Q: Find an equation of the tangent line to the curve at the given point. X + 1 y = (5, –6) X - 6 y =

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Q: find the equations of the tangent line normal to the curve of the given point (0,2) y=(2+x)e^-x

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Q: Find the equation of the tangent line to the curve y = (1 + 2x)? at the point (4, 81). y =

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Q: Find an equation of the tangent line to the curve at the given point. y = sec(x), (7/6, 2/3/3)

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Q: Find an equation of the tangent line to the curve at the given point. y = 2ex + x, (0, 2) y 11

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Q: Find an equation of the tangent line to the curve y =√x at the given point (4,2).

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Q: Find an equation of the tangent line to the curve at the given point. 5x y = x + 3' (2, 2) y =

A: Given curve, y=5xx+3 we have to find the equation of tangent line to the given curve at point (2,2).…

Q: Find the equation of the tangent line to the curve at the given point. y = v2x + I, (4, 3)

A: →Slope, m = dydx→dax+bdx =12ax+b→Equation of straight line passing through (xo,yo) with slope m is…

Q: Find the equation of the tangent line to the curve y = (1+2x)² at the point (3, 49).

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Q: Find equations of the tangent lines to the curve at the given point: f(x, y) = 4x2+y? 2

A: Given:      fx,y=4x2+y2 at 32,1          4x2+y2=0            y2=-4x2 differentiating on both sides…

Q: Find the equation of the tangent line to the curve at the given point. \\ y = 1 + 2x – x°, (1, 2)

A: Given that y = 1+ 2x - x3

Q: Find an equation of the tangent line to the curve at the given point.y = x4 + 5x2 − x, (1, 5)y=

A: Equation of the curve: y = x4 + 5x2 − xSLope of the curve = dy / dx

Q: Find an equation of the tangent line to the curve at the given point. y = √ x,  (81, 9)

A: Given: y=x, (81, 9)

Q: Find an equation of the tangent line to the given curve at the specified point: (4) 2 y = x + 1 ' 5

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Q: Find an equation of the tangent line to the curve at the given point. y = V3 - 33x, (-1,6) y =

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Q: Find an equation of the tangent line to the curve at the given point. y = x3 - 2x + 1, (3,22)

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Q: Find an equation of the tangent line to the curve at the given point y = x3 - 2x + 2, (2,6) y =

A: From the given data:

Q: Find an equation of the tangent line to the curve at the given point. y = v x, (81, 9) y = |0

A: y = xdifferentiate with respect to x,dydx= 12xdydx(81,9)= 1281=118

Q: Find an equation of the tangent line to the given curve at the specified point: 4, x + 3 y =

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Q: Find the equations of the tangent line and normal line to the curve y = (2 + x)e¬* at the given…

A: We will find out the required solution.