Find an equation of the tangent line to the graph of the equation at the given point. x + x arctan y y- 1, (--1) Step 1 Use implicit differentiation to find y'. x2 + x arctan y = y 1, 2x + = y' 1 + (1- -

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find an equation of the tangent line to the graph of the equation at the given point.
(-증)
x +x arctan y = y- 1,
Step 1
Use implicit differentiation to find y'.
x + x arctan y = y- 1,
2x +
1+ v
(1-
!!
y'
Transcribed Image Text:Find an equation of the tangent line to the graph of the equation at the given point. (-증) x +x arctan y = y- 1, Step 1 Use implicit differentiation to find y'. x + x arctan y = y- 1, 2x + 1+ v (1- !! y'
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