Question
Asked Nov 20, 2019
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Find an equation of the tangent line to the graph of the function at the given point.

y = x2ex − 2xex + 2ex,    (1, e)

 

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Expert Answer

Step 1
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The given equation is y xe - 2xe +2e and the point is (1,e) Differentiate the y x'e* -2xe" +2e on both sides dy d d(re2re 2e -(술이음이서숨아~읽이)름이 d d d e2 d d +2 (x2 ex dx dc dx = 2xe +xe* -2e -2xe 2e =re

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Step 2
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dy at x 1 Obtain the value of dy -(1))e dx = e

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