Find an equation of the tangent line to the graph of x² +2y² = 3 at (1, -1).

Q: Find an equation of the tangent line to the curve at the given point. y = In(x2 - 8x + 1), (8, 0) y…

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Q: Find the equation of the tangent line at the given value of x on the curve. y° +xy² -61=x+3y°; x:…

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Q: Find the equation of the tangent line to the curve (y-2)² = 4x +5 at P(1,5).

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Q: Find an equation of the tangent line to y = 24ex at x = 2.

A: Our Aim is to find an equation of tangent line to y=24ex at x=2At x1=2, we have y1=24e2Now we find…

Q: Find an equation of the tangent line to the curve at the given point. y = In(x2 – 5x + 1), (5, 0) y…

A: Given y=lnx2-5x+1 We have to find tangent line at (5,0)

Q: Find an equation of the tangent line to the curve at the given point. 6. y =x² – 3x +1, (2, –1)

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Q: Find an equation of the tangent line to y = xt + 2x2 – x at x = 2

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Q: Find the equation of the tangent line at the given value of x on each curve.  y4(1 - x) + xy = 2; x…

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Q: Find the equation of the tangent line to the curve y³+2xy+x³ = 0 at (-1, –1).

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Q: Find the equation of the tangent line at the given value of x on each curve. y3 + xy - y = 8x4; x =…

A: To Find the equation of the tangent line at the given value of x on each curve. y3 + xy - y = 8x4…

Q: Find an equation of the tangent line to the curve at the given point. y =  4x x + 3 ,…

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Q: Find an equation of the tangent line to the curve at the given point. y = In(x2 - 5x + 1), (5, 0) y…

A: We have to find equation of tangent

Q: Find an equation of the tangent line to the curve y = In(x² – 4x + 1) at x = 4.

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Q: Find the equation of the tangent line to the graph of y = 2x +- at the point (1,5).

A: We have given

Q: Find the equation of the tangent line at the given value of x on each curve.  y3 + xy2 - 3 = x +…

A: Given curve: y3+xy2-3=x+5y2 At x=5: ⇒y3+xy2-3=x+5y2⇒y3+5y2-3=5+5y2⇒y3=8⇒y3=23⇒y=2 ∴ The point is…

Q: Find the equation of the tangent line to the graph of function at the given point y = 1n x^4 ; (1,0)

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Q: Find an equation of the tangent line to the curve atthe given point. y= In (x3 - 7) , (2 ,0)

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Q: Find an equation of the tangent line to the curve at the given point. y = In(x² – 6x + 1), (6, 0) y…

A: As per guidelines we have to solve one question Please repost other questions again

Q: Find the equation of the tangent line to the graph xy^2 − 2y = x^2 at the point (2, −1).

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Q: Find an equation for the tangent line to the graph of y – 3xy + x2 +1 = 0 at the point (2, 1).

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Q: Find the equation of the tangent line to y = at 3 - x X = 1.

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Q: Find the equation of the tangent line to the function y = 2x – 4x + 3 at the point where x = 1.

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Q: Find the equation of the tangent line to y=5x2  at x=0

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Q: Find an equation of the tangent line to the curve at the given point. y = In(x2 – 7x + 1), (7,0) y =

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Q: Find an equation of the tangent line to the curve at the given point. y = In(x2 - 3x + 1), (3, 0)

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Q: Find an equation of the tangent line to the curve at thegiven point.

A: Given: y=2x+1x+2, 1,1 for finding equation of tangent, we need to find slope of tangent  we know…

Q: Find an equation of the tangent line to the curve at the given point. 2x (0, 0) (x + 1)2'

A: The given curve y=2xx+12, at the point 0,0

Q: Find the slope of the tangent line to the curve x²-3y=4y³ at x=-1

A: Solution: Consider the given equation of the curve is: x2 -3y = 4y3or4y3 = x2  -3y Differentiating…

Q: Find the equation of the tangent line to the graph of j f (x) =- -5e2* at the point (0, -5).

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Q: Find the equation of the tangent line at the point (1,−3) to the curve defined implicitly below. x3…

A: The line is tangent to the given hyperbola at (1,-3).Tangent line is a straight line.Therefore, the…

Q: Find an equation of the tangent line to the curve at the given point y = x³ – 3x + 1, (2,3)

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Q: Find the equation of the tangent line at the given value of x on the curve. 3y +xy-y = 192x*; x=1

A: Given eqn : 3y3+xy-y=192x4  ,  x=1 So when x =1 3y3+xy-y=192x4=3y3+y-y=192= y3 = 64= y = 4 Now find…

Q: Find the equation of the tangent line at the given value of x on the curve. y+xy² -22=Dx+5y; x= 5

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Q: Find the equation of a tangent line to the curve y=xe2x at the point where x=1

A: We need to find the equation of a tangent line to the curve y=xe2x at the point where x=1. Now,…

Q: Find the equation of the tangent line at the given point: 5x² – 2xy + y² = 13 at (1, -2)

A: Given,                            .......(1) Point (1,-2)

Q: Find the equation of the tangent line on the curve f(x) = V5x + 6 at x = 2.

A: Proceed as shown below...

Q: Find the equation of the tangent line at the given point on the curve. 327x 3x² + 3y² , 109y 2 10…

A: As we know that; The expression for the equation of the tangent line is: y-y1=mx-x1 Where, m is the…

Q: 2x2 y = Зх — 1

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Q: Find the equation of the tangent line to the graph of x³ + y³ – 3xy = 0 at the 3 3 point ).

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Q: find an equation for the tangent line to the graph of y=(5-2x)^2 at (3,1).

A: Explanation of the answer is as follows

Q: Find an equation for the tangent line to y =-3x- at the point x =-1.

A: We have to find equation of tangent line to the curve y=-3x2-1x3 at the point x=-1 To find the…

Q: Find an equation of the tangent line to the graph of x° + 3xy² + y = 15 at the point (1, 2). y=

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Q: Find the equation of the tangent line to the graph of x^2y-xy^4=-1830 at (3,5)

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Q: Find an equation of the tangent line to the given curve at the specified point. y = (4x)/(x+4)  (4,…

A: To find the equation of the tangent line to the given curve at the specified point, Differentiate…

Q: Find the equation of the tangent line at the point (1,0) to the curve implicitly defined by In(x +…

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Q: Find the equation of the tangent line to the curve g(x) = 4x² – 3x + 2 at the point (1, 3).

A: As we know that; The expression for the equation of the tangent line is: y-y1=mx-x1 Where; m is the…

Q: Find the equation of the tangent line at the given value of x on the curve y° + xy° - 4 = x + 4y“;…

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Q: Find the equation of the tangent line to the graph of x2y2+4xy = 0 at the point (-4, 1).

A: Given: x2y2+4xy=0  at point -4,1

Q: Find an equation of the tangent line to the curve at the given point. y = (x2 - 1)/(x2 + x + 1')…

A: Given:         y=(x2−1)(x2+x+1)   for (1,0).