Question
Asked Aug 31, 2019
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Find, correct to the nearest degree, the three angles of the triangle with the given vertices.

P(3, 0),      Q(0, 2),      R(5, 5)
RPQ = °
PQR = °
QRP = °
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Expert Answer

Step 1

To find the three angles of the triangle formed with the vertices P(3,0), Q(0,2), R(5,5).

Obtain the length of the sides of the triangle PQR using the distance formula as follows.

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(0-3)' +(2-0) = v9+4 13 ORb(5-0)+(5-2) 25+9= 34 PR= c= {(5-3)+(5-0) /4+ 25 = 29 \Pg=a=

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Step 2

Find the angles using cosine rule as follows. Obtain the value of angle P as given below.

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a bc2bccos P bca cos P 2bc 34+29-13 2/986 50 2/986 50 = cos 2/986 =37.23 370

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Step 3

Obtain the value of angle Q ...

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b2 ac22accosQ ac-b cosQ 2ac 13+29-34 2/377 2/377 cos 2 377 = =78.11 780

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