ex/y = 4x - y
Let's differentiate both sides with respect to x.
1. The chain rule of differentiation
2. Derivative of ex/y = d(ex/y) / dx = ex/y.d(x/y) / dx
3. d(x/y) = 1/y -x/y2.dy / dx
Hence, LHS on differentiation = d(ex/y) / dx = ex/y.(1/y -x/y2.dy / dx)
RHS on differentiation = 4 - dy / dx
Hence, ex/y.(1/y -x/y2.dy / dx) = 4 - dy / dx
Regroup the terms containing dy / dx on LHS, we get
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