Find dy/dx for the following :1) y = x3 + sin x² + sin-1 5x7) y = 3ln (sec2x) eln(cos-1x²)(sin/xcsc /x9) y* = sin-1 x2) y = 32x + In (sin x²) + In(sin-1 5x)8) у%3D3) y = In (32x) + sec (Inx²) + tan-1(In5x)4) y = 3(In2x) +e(cscx²) + 4(sec-15x)%3D10) y = xtanx + sin-ly5) y = 3(sec2x) (cos-1x²)11) (Vy)* = (In tanx)(x*)(sin x)*%3D6) у3= (cot x²)**(cot-!x²)12) (/y)* %D sec-1 (х)(n/x) (4-еск) (tan-1е3:)(6cot5x) e(2 In 9x)13) у %3D

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Answered: Find dy/dx for the following : 1) y =…

Find dy/dx for the following : 1) y = x3 + sin x² + sin-1 5x 2) y = 32x + In (sin x²) + In(sin-1 5x) 3) y = In (32*) + sec (Inx²) + tan-'(In5x)

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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Optimization

Optimization comes from the same root as "optimal". "Optimal" means the highest. When you do the optimization process, that is when you are "making it best" to maximize everything and to achieve optimal results, a set of parameters is the base for the selection of the best element for a given system.

Integration

Integration means to sum the things. In mathematics, it is the branch of Calculus which is used to find the area under the curve. The operation subtraction is the inverse of addition, division is the inverse of multiplication. In the same way, integration and differentiation are inverse operators. Differential equations give a relation between a function and its derivative.

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In mathematics, the process of integration is used to compute complex area related problems. With the application of integration, solving area related problems, whether they are a curve, or a curve between lines, can be done easily.

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Area refers to the amount of space a figure encloses and the number of square units that cover a shape. It is two-dimensional and is measured in square units.

Question

Find dy/dx for the following :
1) y = x3 + sin x² + sin-1 5x
7) y = 3ln (sec2x) eln(cos-1x²)
(sin/x
csc /x
9) y* = sin-1 x
2) y = 32x + In (sin x²) + In(sin-1 5x)
8) у%3D
3) y = In (32x) + sec (Inx²) + tan-1(In5x)
4) y = 3(In2x) +e(cscx²) + 4(sec-15x)
%3D
10) y = xtanx + sin-ly
5) y = 3(sec2x) (cos-1x²)
11) (Vy)* = (In tanx)(x*)(sin x)*
%3D
6) у3
= (cot x²)**(cot-!x²)
12) (/y)* %D sec-1 (х)
(n/x) (4-еск) (tan-1е3:)
(6cot5x) e(2 In 9x)
13) у %3D

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