@ docs.google.com/forms ()} find force in member BC by by the .method of joints 346 kN (@ 446 O 546 O 646 O non of these O spaomd) i docs.google.com/formsfind force in member BC by by the.method of joints5 m5 m5 m5 m5 mA5 mE5 m30 kN20 kN34.6 kN44.654.664.6 Onon of these Oمحو التحدید

Method of joints at A: Applying equilibrium conditions: ∑Fy=0FABsin600-30=0FAB=34.641 kN

Answered: find force in member BC by by the…

find force in member BC by by the .method of joints 5 m 5 m 5 m 5 m 5 m A 5 m E 5 m 30 kN 20 kN 34.6 kN 44.6 O 54.6 64.6 O non of these O B.

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter5: Three-dimensional Equilibrium

Section: Chapter Questions

Problem 5.1P: Bar AB of negligible weight is supported by a ball-and-socket joint at B and two cables attached at...

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Concept explainers

Axial Load

When a bar of the uniform cross-section is acted by a load, such that the load acts along the longitudinal axis of the bar, such kinds of loadings are known as axial loadings. In general terms, a load is an external force acting on a component. An axial load acts perpendicular to the geometric cross-section of the component. Based on the direction of the application of the load, an axial load can be tensile or compressive. The analysis of bodies under the action of axial loads is generally studied under the branch of mechanics, known as statics.

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@ docs.google.com/forms ()} find force in member BC by by the .method of joints 346 kN (@ 446 O 546 O 646 O non of these O spaomd)

i docs.google.com/forms
find force in member BC by by the
.method of joints
5 m
5 m
5 m
5 m
5 m
A
5 m
E
5 m
30 kN
20 kN
34.6 kN
44.6
54.6
64.6 O
non of these O
محو التحدید

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