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Q: If geR[a,b] and if hGx) = gCa) except for a finite num ber of points in [a, b], then prove that…
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Q: Let's compare the cardinalities of N and I.
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Q: Let S={xEZ:x+2=6(mod 15)}. Then Sis is the empty set a countable set is an uncountable set
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Q: ofind all voots ecilmal Places.
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Q: (1) Let A and B be sets prove the following. (b) ACB if and only if An B = A. %3D
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Q: yoint each. On the Cverage. Une jaint defectuve to be free from i How moy defective joints in a gets…
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Q: Prove: Vn,meZ, if n and m are odd, then n-m is odd.
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Q: şa,6şc2.Debine a selation I on. pl2) which satisfies. For all set A and B in P(X) AJB ANB+
A: Given x={a, b, c}P(x)={ {a} , {b}, {c}, {a,b}, {a,c}, {b,c}, {a,b,c}, ∅}a relation onJ: P(x)…
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A: Archimedean property named after the mathematician Archimedes. The set of real numbers ℝ has the…
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Q: 2) het A, B and non- dijoint diagranı be Three Cveyla Ony using sets von Show (B-C)Ule- A) # A-8
A: firstly, we will draw all given set region then we comparing both side
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Q: Use set identities or different proof method to show that: (A U B) n (B U A°) = B
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Q: (3) Let S = {; Find with prove :m eN,n E N}. %3D suprenum of S. (4) What is an unbounded set?
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A: 1. a ∀ x ∈ R, ∀ x ∈ R, x2+y2 ≥ 2xy TRUE. Because, ∀ x ∈ R, and ∀ x ∈ R we have (x-y)2 ≥ 0.…
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Q: Let R and S be two posets on a set X. Are RNS, RUS, R\ S, also posets on X as well? If they are,…
A: Given R and S are two Poset on a set X. (1) Consider R∩S. Since R and S are poset, therefore each…
Q: Let S={xEZx+2=6(mod 15)}. Then S is* is the empty set a countable set is an uncountable set
A: A countable set is either finite or denumerable. Given: S=x∈Z:x+2≡6mod 15
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Q: Prove by unduclion Hhat if ne IN - 31,2,3,...f aud 9> 2
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Q: Let A1, A2, ... , An be any n sets, n 2 1. Show that (U-1 Ar) = U=1 Ar %3D
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Q: Let A = {a, a, b, c} and B = {a, b, c}. Prove that A = B. Thus, the number of times an element is…
A: Given A={a,a,b,c} and B={a,b,c} we have to show that A=B, for this we will show that A⊂B and B⊂A…
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Q: prove that (1, 6) 13 an o pen set 13 an open çet.
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Q: Show that if A and B sets then A – B = ANB
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Q: Prove (((LOM)-N) U(N-(LUM))) < (LU (MUN)) L, M, N are sets.
A: To prove: L∩M-N∪N-L∪M⊂L∪M∪N
Q: Let S={xEZx+3=4(mod 20)}. Then S is a countable set is the empty set is an uncountable set
A: See solution below
Q: Let X = {a, b, c} and R={(c, b),(a, c)}. Then Check the all properties reflexive,symmetric,…
A:
Q: 5. Deduce from (4) that the set {2} 2-: n = 1, 2, 3, ... is closed in R.
A: Given set S =2 ∪2-1n : n=1 2, 3 , . . .
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