need help with solving b) In this task we will investigate how we can estimate integras we don't have a chance at by normalruels by using taylors formula. You can use 2 < e < 3 without justification and that the functiongiven g(x) = e* is growing.a) Justify that all real numbers x and positive integers n, so ise 2x= 1+ e* +e 3xenx+п!eet(n+1)xee Sx(n + 1)!For a sy E (0, ex). justify that2en+1_ 1(n+1)(n+1)!b) Find n so thate Sxe(n+1)x-dx < 33(n+1)!en+1–1(n+1)(n+1)!27en+112 (n + 1)(n + 1)!< 0.05?1Use the information above to calculateeetdx with an error less than 0.05

For (b), We need to find n so that 272en+1-1n+1 (n+1)!<0.05. Notice that solving this…

Answered: Find n so that 27 en+1 – 1 < 0.05? 2 (n…

Find n so that 27 en+1 – 1 < 0.05? 2 (n + 1)(n + 1)! Use the information above to calculate eet dx with an error less than 0.05

Linear Algebra: A Modern Introduction

4th Edition

ISBN:9781285463247

Author:David Poole

Publisher:David Poole

Chapter4: Eigenvalues And Eigenvectors

Section4.6: Applications And The Perron-frobenius Theorem

Problem 17EQ

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Question

need help with solving b)

In this task we will investigate how we can estimate integras we don't have a chance at by normal
ruels by using taylors formula. You can use 2 < e < 3 without justification and that the function
given g(x) = e* is growing.
a) Justify that all real numbers x and positive integers n, so is
e 2x
= 1+ e* +
e 3x
enx
+
п!
eet
(n+1)x
e
e Sx
(n + 1)!
For a sy E (0, ex). justify that
2
en+1_ 1
(n+1)(n+1)!
b) Find n so that
e Sx
e(n+1)x
-dx < 33
(n+1)!
en+1–1
(n+1)(n+1)!
27
en+1
1
2 (n + 1)(n + 1)!
< 0.05?
1
Use the information above to calculate
eet
dx with an error less than 0.05

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