Find sec 2x -dx. tan 2x cot82x (4sec 22x-1) (A) 12 1 1 I B 12 tan 2x 16 tan 82x Ⓒ -co1²2x-co1³21+ C 12 16 3csc Ⓒ - - (cor^2x)(1+x6x¹2x) + C +C - + +C +C

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A: Solution of the problem as follows

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A: topic - limits a3+b3=(a+b)(a2+b2-ab)

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A: Topic:- integration

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A: answer is in next step

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A: answer is in next step

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Q: 18) fin

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A: We can solve this as follows:

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A: To evaluate: I=∫x-2sec41xtan521xdx Substitute 1x=t⇒-1x2dx=dt⇒x-2=-dt So, I=∫sec4t  tan52t…

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A: Please see the answer below.

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A: answer is in next step

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