Find symmetric equations of the normal line to the surface 3xy-z = 0 at the point (-4, -2, 24). O x+4 6 x +4 12 == O 3(x-4)=3(y-2) = −(z-24) Ox+4 6 = y+2 12 == y+2 6 =z=24 O 3(x-4)=3(y-2)=(z-24) y+2 12 =z=24 =z=24

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