Find T, N, and B for the given space curve. r(1)= (6+t)i + (2 + In (sec t))j-3k, - T/2

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section: Chapter Questions
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Find T, N, and B for the given space curve.
r(t)= (6+t)i + (2 + In (sec t))j- 3k, - T/2 <t < T/2
O A. T-(cos t)i + (sin t)j; N = (- sin t)i + ( cos t)j, B = k
O B. T=(- cos t)i - (sin t)j; N=(sin t)i – (cos t)j, B = - k
Oc.
O C. T= (- cos t)i - ( sin t)j;N = (- cos t)i +(sin t)j, B = k
O D. T-(cos t)i - (sin t)j; N=(- sin t)i - (cos t)j. B = - k
Transcribed Image Text:Find T, N, and B for the given space curve. r(t)= (6+t)i + (2 + In (sec t))j- 3k, - T/2 <t < T/2 O A. T-(cos t)i + (sin t)j; N = (- sin t)i + ( cos t)j, B = k O B. T=(- cos t)i - (sin t)j; N=(sin t)i – (cos t)j, B = - k Oc. O C. T= (- cos t)i - ( sin t)j;N = (- cos t)i +(sin t)j, B = k O D. T-(cos t)i - (sin t)j; N=(- sin t)i - (cos t)j. B = - k
Expert Solution
Step 1

Find r'(t) by differentiating r(t) with respect to t.

r(t)=6+ti+2+lnsec tj-3kr'(t)=i+sec t·tan tsec t j-0k=i+tan t j

Now, find r(t). Use the identity 1+tan2 θ=sec2 θ.

r(t)=12+tan t2=1+tan2 t=sec2 t=sec t

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