Find the absolute extrema of the given function on the indicated closed and bounded set R. f(x, y) = x² - 4y² - 4x + 24y; R is the square region with vertices (0, 0), (0, 8), (8, 8) and (8, 0) Absolute maximum: i Absolute minimum: i

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter9: Systems Of Equations And Inequalities
Section: Chapter Questions
Problem 12T
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Could you please help me? Why is it incorrect? Also, in the 2nd photo, I need a step-by-step solution for the final answer. Thank you.

* Incorrect.
Find the absolute extrema of the given function on the indicated closed and bounded set R.
f(x, y) = x² - 3y² - 6x +12y; R is the square region with vertices (0, 0), (0, 9), (9, 9) and (9, 0)
Absolute maximum: 27
Absolute minimum: -135
Transcribed Image Text:* Incorrect. Find the absolute extrema of the given function on the indicated closed and bounded set R. f(x, y) = x² - 3y² - 6x +12y; R is the square region with vertices (0, 0), (0, 9), (9, 9) and (9, 0) Absolute maximum: 27 Absolute minimum: -135
Find the absolute extrema of the given function on the indicated closed and bounded set R.
ƒ(x, y) = x² − 4y² − 4x + 24y; R is the square region with vertices (0, 0), (0, 8), (8, 8) and (8, 0)
Absolute maximum: i
Absolute minimum: i
Transcribed Image Text:Find the absolute extrema of the given function on the indicated closed and bounded set R. ƒ(x, y) = x² − 4y² − 4x + 24y; R is the square region with vertices (0, 0), (0, 8), (8, 8) and (8, 0) Absolute maximum: i Absolute minimum: i
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