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A: In this problem we need to use of Lagrange's multiplier method. We use gradient also.
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A: Explanation of the answer is as follows
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- Find the exact global maximum and minimum values of the function g(t)=5te^−3t if t>0 global maximum at t=t= global minimum at t=t= (Enter none if there is no global maximum or global minimum for this function.)a. Let y=f(x) be the particular solution to the given differnetial equation with the initial condition f(2)=1. Write an equation for the line tangent to the graph of y=f(x) at x=2. Use your equation to approximate f(2.1). b. Find the particular solution to the given differnetial equation with the initial condition of f(2)=1.4.Consider the functionf(x,y)=−x2−y2+6x+2y a.Find the values of x∧y that correspond to the stationary point(s) of this function. b.Determine whether the point(s) you identified in part (a) is a maximum, a minimum, or neither
- 1. A critical number of f′(x) is an inflection point of f(x).True or False 2. If the radius of a circle is increasing at a constant rate, then so is the circumference.True or False 3. If two variables x and y are functions of t and are related by the equationy = 1 −x^2, then dy/dt = −2x.True or False 4. When finding the global minimum of a function on an interval, you must usethe first or second derivative test to verify that your point is a global minimum.True or FalseFind the absolute minimum value on (0,infinity) for f(x)=4e^x/x^2