Find the area of the shaded region. y x = y - 4 y 15 5 4'2 2 -6 -5 -4 3 -2 X= y-y -2 -4 -6F

Q: Find the area of the shaded region. NOTE: Enter the exact answer. x = y 1 x = y2

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Q: Find the area of the shaded region. square units y y = x V1-x? y= 0 X 1 1 y= 0 HIN

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Q: 4. Determine the area of the shaded region. -y =Dx y= x²2

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Q: Find the area of the region enclosed by y = 16x and y = 2x*. 1 a. 10 101 O b. 5 96 C. 5 96 Od. 5 O…

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Q: Find the area of the shaded region. y (1, 7e) 15 y = 7 e 10 5 y=7xe -1.0 -0.5 0.5 1.0 1.5 2.0 20

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Q: Find the area of the shaded region. y y= 9x- x² 20 15 (7, 14) 10 5 y = 2 x 4 6. 8 10 2.

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Q: Find the area of the shaded region. y y= v x 1 1, 1) X= 27 1 y = 10 15 20 25 2. 4.

A: Given query is to find the area of the shaded region.

Q: Find the area of the shaded region. y y = Vx 3 마1, 1) x = 27 1 y = X 5 10 15 25 20 2.

A: The area under the graph can be determined by integration. Let, Boundary points are, x1=1 and…

Q: d) Evaluate the area of the shaded region. y y =x'+1 -1 1

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Q: Find the total area of the shaded region. Ay 10 Q 6- y = 5 y=x y= 2- 20 10

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Q: Evaluate ∫∫.xy dA, where R is the region in the 3rd quadrant with circles inside x^2+y^2=4 and…

A: Let us first draw the graph of Region R Here,  required region R is the region ABCD. using the…

Q: Determine the area of the shaded region given the following figure. 8- X=V/ x= y2 - 6 X -i0 10 -8…

A: NOTE: Refresh your page if you can't see any equations. . here we have to find the intersection…

Q: Find the area of the shaded region below. yA x= y? – 4y (-3, 3) x = 2y – y? Area =

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Q: Find the area of the shaded region. y = x² +1 %3D 5 y = x -1 A 23 2. 2/2

A: Given

Q: Find the area of the shaded region below. x= y? – 4y (-3, 3) x= 2y – y?

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Q: Find the area of the shaded region. y x = y - 7 y = 1 x = ey -4 -8 -2 2 4 -6 y = -1 -2 -3 2.

A: We have to find the area with respect to y here. To find the area between x=e^y and x=y^2-7 we have…

Q: Find the area of the shaded region. y 4h 3 y = V x 2 1 1, 1) X = 27 1 y = 5 10 15 25 20

A: Topic- application of integration

Q: Find the area of the shaded region. NOTE: Enter the exact answer. y = x2 + 2 A =| y = x 2

A: We want to find the shaded area.

Q: Find the area of the shaded region.

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Q: Find the area of the shaded region. y 4 3 y= V x 2 마 1, 1) X = 27 y : to 5 10 15 20 25

A: The sketch of the region bounded by the curves is  To evaluate: The area of the shaded region.

Q: What is the area of the region in the first quadrant enclosed by y= e 4. and the line y0.5. 0.516 sq…

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Q: nd the area of the shaded region. y x = y° - 10 y 10 (-75/4, 15/2) -30 - 20 -10 -5 x= 5 y- y

A: We have to find the  shaded area from the given

Q: Find the area of the shaded region. y y= xV4 x y=0 2 y= 0 -2 SQuare units 21

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Q: Find the area of the shaded region. y = x2 + 3 (2,7) (0,3) 23 A) 3 26 В) 3 22 25 D) 3

A: As per the guidelines we can solve 1 problem only.

Q: y = 1/x2, y=9, x=6 Find the area of the region?

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Q: Find the area of the shaded region: 1. yA x= 2 2, 4) y= x? y= 0

A: We will find the area of shaded region as following.

Q: Find the area of the shaded region. y 15 y=7x-x² 10 (5, 10) 5 y=2 x 4 8.

A: The area of the shaded region is, 125/6  the detailed solution is as follows below:

Q: ind the area of the shaded region. y= 2x? + x - 6 y=x2.4 3+ 2 19

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Q: Find the area of the shaded region. NOTE: Enter the exact answer. y = x² + 3 y = x 4

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Q: x=(y– 13 2- x=3-y 1 T= 2Vy

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Q: Find the area of the shaded region. y x= 2 y = 2 e* y= 5 x– 1

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Q: Find the area of the shaded region. y 3| 2 x= y - 3 y = 1 X=

A: To find- Area of shaded region.

Q: Find the area of the shaded region. y 14 y= 7x- x² 12 10 (5, 10) 6 4 2 y=2 x 2 4 6 8 CO

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Q: Find the area of the shaded region. y 15 y = 7x-x² 10 (5, 10) 5 y= 2 x 4 6. Enhanced Feedhaclo

A: We can application integration in order to solve the given problem.

Q: Find the area of the shaded region. 4+ x = y? 2+ 9. 4 6. 8. 2. -2+ 10* 4 Select one or more: Oa. 18…

A: we have to find the area of the shaded region

Q: Find the area of the shaded region. 1) y = X - 3 (16,1) 16 (0,-3) 29 A) - 38 16 B) D)- 3

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Q: Find the area of the shaded region below. y x = y² – 2 y=1 x=e> y=-1 Area =

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Q: Find the area of the shaded region. x = -y 2 x = 2 - -2 A B 10 3 2.

A: Given query is to find the area of the shaded region.

Q: Find the area of the shaded region. y y = x 2 11, 1) X= 27 1 y= 5 10 15 20 25 3.

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Q: Find the area of the shaded region. y =x – 2 2- y= Vx 1+ + 3 4 -1 square units 2.

A: Given that: To find: Area of the shaded region.

Q: Find the area of the shaded region. NOTE: Enter the exact answer. y = x2 + 2 %3D y = x 4.

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Q: Find the area of the shaded region. y 3 x= y - 3 y = 1 x = ey - 4 -2 2 4 y = -1 -2 -3 2.

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Q: Find the area of the shaded region. y = x² + 1 ... 5 y = x -1 2.

A: In given problem we find the area by using the Definite Integration .

Q: Find the area of the shaded region below. yA x= y? – 4y (-3, 3)– x= 2y – y? Area =

A: We have to find the the area of the shaded region in the given figure.

Q: Find the area of the shaded region. NOTE: Enter the exact answer. y = x² + 4 A = y = x

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Q: Determine the area of the shaded region given the following figure. Ay 8- x = 2y x=y? - 8 -12 12 -8-

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Q: Find the area of the shaded region below. y 4 x= y² -2 y = 1 x= e" y=-1

A: Given

Q: Find the area of the shaded region. r = 4 + 3sin(0) 6- y -6 -2 6. 2.

A: Given that: r=4+3sin(θ)

Q: Find the area of the shaded region. y 14 (1, 5e) 12 10 y= 5 e 6 4. 2 y = 5 xe

A: Given:-Rrgion bounded byy=5ex, y=5xex2 and y-axisTo find: the area of shaded region

Q: nd the total area of the shaded regions. Ay 25 y= X 25 = 20- 15 10 5- -8 -4 -2 (5- 9. -10- 寸

A: Given query is to find the total area of the shaded region.

Optimization

Optimization comes from the same root as "optimal". "Optimal" means the highest. When you do the optimization process, that is when you are "making it best" to maximize everything and to achieve optimal results, a set of parameters is the base for the selection of the best element for a given system.

Integration

Integration means to sum the things. In mathematics, it is the branch of Calculus which is used to find the area under the curve. The operation subtraction is the inverse of addition, division is the inverse of multiplication. In the same way, integration and differentiation are inverse operators. Differential equations give a relation between a function and its derivative.

Application of Integration

In mathematics, the process of integration is used to compute complex area related problems. With the application of integration, solving area related problems, whether they are a curve, or a curve between lines, can be done easily.

Volume

In mathematics, we describe the term volume as a quantity that can express the total space that an object occupies at any point in time. Usually, volumes can only be calculated for 3-dimensional objects. By 3-dimensional or 3D objects, we mean objects that have length, breadth, and height (or depth).

Area

Area refers to the amount of space a figure encloses and the number of square units that cover a shape. It is two-dimensional and is measured in square units.