Ex: Find the area of the triangle with vertices P(1,-1,0), Q(2,1,-1) and R(-1,1,2). Area of the parallelogram= |PQ x PR| = 16i + 6j| = v62 + 62 = 6v2 %3D Area of a triangle= area of parallelogram = (6v2) = 3V2 %3D

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.3: Lines
Problem 7E
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Ex: Find the area of the triangle with vertices P(1,-1,0), Q(2,1,-1) and R(-1,1,2).
Area of the parallelogram= |PQ x PR| = |6i + 6j| = v62 + 62 = 6v2
1
Area of a triangle= area of parallelogram =(6v2) = 3V2
Transcribed Image Text:Ex: Find the area of the triangle with vertices P(1,-1,0), Q(2,1,-1) and R(-1,1,2). Area of the parallelogram= |PQ x PR| = |6i + 6j| = v62 + 62 = 6v2 1 Area of a triangle= area of parallelogram =(6v2) = 3V2
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