Question
Asked Dec 17, 2019
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Find the area.

 

y = 3 cos(4x),    y = 3 − 3 cos(4x),    0 ≤ x ≤ π/4

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Expert Answer

Step 1
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y = 3 cos (4x),y=3-3cos(4x),0<xs 4 Find the area enclosed by the curv urves 5- y = 3-3 cos(4x) (1/12, 1.5) y = 3 cos (4x)

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Step 2
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The area enclosed by the curves is given by, A=[f(x)-g(x) dx. A = [3 cos (4x)-(3–3cos(4x)) dx Bcos (4x)-(3-3cos (4x)) dx+ [ |(3– 3 cos ( 4x))– 3cos(4x) dx (6cos(4x)-3)dx+[(-6cos(4x)+3)dx 12 (6cos(u)-3) dx+(-6cos (u)+3)dx (u = 4x, dx = 4) On further simplification,

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Math

Calculus