Find the capacitance (in pF) of paralel-plate capacitor containing two dielectrics with cri-3 and cr2 4.5. cach comprising one-half the volume. The area of the plates is 20 cm2 and the distance between them is 1 cm. O 7.30 O 4.43 O .81 O 6.64

Find the capacitance (in pF) of paralel-plate capacitor containing two dielectrics with cri-3 and cr2 4.5. cach comprising one-half the volume. The area of the plates is 20 cm2 and the distance between them is 1 cm. O 7.30 O 4.43 O .81 O 6.64

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Concept explainers

Dielectric Breakdown

A dielectric is a material with low electrical conductivity and so is classified as an insulator. Dielectric materials are used to block the flow of electricity through them, allowing them to behave as an insulators. They can also be used to store electric charge or improve capacitance.Dielectrics have no free electrons for conduction because electrons are tightly bound to the nucleus. Because dielectrics contain a small number of electrons for electrical conductivity, they have a dipole. The two primary roles of dielectrics in electrical devices are insulation and electrical energy storage. An electric field polarizes the dielectric, and the polarization of the molecules allows dielectric materials to store charge.

Question

Find the capacitance (in pFl of
paralel-plate capacitor containing
two dielectrice with ert= 3 and er2 -
4.5. each comprising one-half the
volume. The area of the plates is 20
cm2 and the distance between them
is tcm,
7.30
4.43
6,64
Find the capacitance (in pF) between
the two conducting spheres with at r
=9 mm and r= 19 mm. If the
dielectric between them having er = 3
8.0
76
5,0
5.7
O O O

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