Find the centroid of the region shown, not by integration, but by locating the centroids of the rectangles and triangles and using additivity of moments. y 2 1 -3 -2 -1 2 3 4 5

Calculus: Early Transcendentals
8th Edition
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Author:James Stewart
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find the centroid of the region shown, not by integration, but by locating the centroids of the rectangles and triangles and using additivity of moments.
y
5-
1
-3
-2
-1
1
4
5
1 5
(x, y) =
12' 6
3.
Transcribed Image Text:Find the centroid of the region shown, not by integration, but by locating the centroids of the rectangles and triangles and using additivity of moments. y 5- 1 -3 -2 -1 1 4 5 1 5 (x, y) = 12' 6 3.
The centroid of any triangle is located at the point of intersection of the medians. Recall that a median is a line segment from a vertex to the midpoint of the opposite side. Recall also that the medians
intersect at a point two-thirds of the way from each vertex (along the median) to the opposite side.
Find the centroid of the region shown, not by integration, but by locating the centroids of the rectangles and triangles (from the above information) and using additivity of moments.
y
2
-3
-2
-1
1
3
(X, y) =
Transcribed Image Text:The centroid of any triangle is located at the point of intersection of the medians. Recall that a median is a line segment from a vertex to the midpoint of the opposite side. Recall also that the medians intersect at a point two-thirds of the way from each vertex (along the median) to the opposite side. Find the centroid of the region shown, not by integration, but by locating the centroids of the rectangles and triangles (from the above information) and using additivity of moments. y 2 -3 -2 -1 1 3 (X, y) =
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