Find the complexity of the following blocks of code or algorithm's description. [Note: your answer must show the steps that lead to your final answer] 1) count = 0 for i = 1 to n do for k = 1 to n do for (j = 2; j
Find the complexity of the following blocks of code or algorithm's description. [Note: your answer must show the steps that lead to your final answer] 1) count = 0 for i = 1 to n do for k = 1 to n do for (j = 2; j
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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![Question 4:
Find the complexity of the following blocks of code or algorithm's description.
[Note: your answer must show the steps that lead to your final answer]
1) count = 0
for i = 1 to n do
for k = 1 to n do
2)
for i = 1 to n do
count += i
count = 1
for (j = 2;j<n;j *= 2)
count = i +k + j;
for k = 1 to n do
count *= k
end for
k +=2
while j< n do
count +=j
j*= 2;
end while
The algorithm solves the problem
of size n by recursively solving
sub-problems of size n – 1, and
then combining the solutions in
Q(n) time.
end for
end for
3) The algorithm solves the problem of 4)
size n by dividing it into 64 sub-
problems of size n/8, recursively
solving each sub-problem, and then
combining the solutions in O(n?)
time
5) The algorithm solves the problem
by breaking it into 8 sub-problems
of 1/4 the scale, recursively solving
each sub-maze, and then
combining the solutions in linear
time](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdeec4bd4-2c28-47bc-8577-aa629f0c130e%2Fc7587204-3020-4638-91d5-8c79ed1025a7%2Fqooqk38_processed.png&w=3840&q=75)
Transcribed Image Text:Question 4:
Find the complexity of the following blocks of code or algorithm's description.
[Note: your answer must show the steps that lead to your final answer]
1) count = 0
for i = 1 to n do
for k = 1 to n do
2)
for i = 1 to n do
count += i
count = 1
for (j = 2;j<n;j *= 2)
count = i +k + j;
for k = 1 to n do
count *= k
end for
k +=2
while j< n do
count +=j
j*= 2;
end while
The algorithm solves the problem
of size n by recursively solving
sub-problems of size n – 1, and
then combining the solutions in
Q(n) time.
end for
end for
3) The algorithm solves the problem of 4)
size n by dividing it into 64 sub-
problems of size n/8, recursively
solving each sub-problem, and then
combining the solutions in O(n?)
time
5) The algorithm solves the problem
by breaking it into 8 sub-problems
of 1/4 the scale, recursively solving
each sub-maze, and then
combining the solutions in linear
time
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