Find the depreciation for the indicated year using MACRS cost-recovery rates for the properties placed in service at midyear. Round dollar amounts to the nearest cent. Property Class: 3-year Depreciation year: 3 Cost of property: $97,700
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Find the
Property Class: 3-year
Depreciation year: 3
Cost of property: $97,700
$14,469.37 - answer
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- MODIFIED ACCELERATED COST RECOVERY SYSTEM Using the information given in Exercise 5Apx-1B and the rates shown in Figure 5A-4, prepare a depreciation schedule showing the depreciation expense, accumulated depreciation, and book value for each year under the Modified Accelerated Cost Recovery System. For tax purposes, assume that the computer has a useful life of five years. (The IRS schedule will spread depreciation over six years.)An investment group faces following GAP figures and rate sensitives. Time GAP Cumulative gap 0-3 months -140 -120 3-6 months +60 -94 6-12 months +1725 +1494 Interest rate rose by 200 basic points (2%) at the begining of first time bucket(0-3 months) and remained there for the next year. Estimate the effect on net interest revenue for the coming 1 year period. Repricing occurs at the start of each period.Service Output MethodGiven:FC = 800,000.00 pesosSV = 200,000.00 pesosn = 5 yearsOutput in year 1 = 300 unitsTotal output in 5 yrs = 1000 unitsa. Depreciation per unit = ?b. Book Value at year 1= ?
- Did not apply any discount rate of 10%. How are we calculating this income from annual operating cost? what's the logic Income from annual operating cost= (Annual cost * % of reduction * no of the year) =$110,000* 50% *7 =$385,00profile-image Time remaining: 00 : 09 : 41 Accounting We have the following data for a power plant: 1 MW CENTRAL ECONOMIC BALANCE Power: 1 Mwa Maintenance cost: 3% per year Initial cost of operation: 5% per year Regulated Rate: $0.015/kWh (20 years) Project cost = $750,000.00 Plant factor= 60% Energy: 5256000 KWh Income from regulated tariff: 78840 Annual revenue increase: 6% Initial maintenance cost/year of annual maintenance (2% installation): $ 22,500.00 Annual maintenance increase: 5% Initial cost of operation/year (1% Installation) $ 37,500.00 Annual operation increase: 3% It is assumed that in year 10, an equipment update will be carried out whose cost will be 25% of the value of the investment = $187,500.00 SOLVE: In what year will the investment be recovered?Construction cost for year 1 & 2 = $6 mil , $12 million totoal Operation and Maintenance (op. and main) Costs = 3rd yr (1st yr of operation) to 25th yr (last yr of operation). with nominal $800,000 in 3rd yr Annual electricity sales = year 3~25 , with nominal $850,000 in 3rd yr annual growth rate of the op. and main costs = 1%, annual growth rate of revenue = 3% social discount rate = 0.04 inflation = 0.02 terminal value = $23 mil. (nominal) 3) an additional $50,000 is added every 3 years for a special "cleaning" and therefore the project life has another 6 years with the terminal value unchanged. would this change be justified?
- A company expects the cost of equipment maintenance to be $5,000 in year one, $5,500 in year two, and amounts increasing by $500 per year through year 15. At an interest rate of 0.08 per year, the present worth of the maintenance cost is nearest to Note: The given interest is already in decimal form. Do not round in between solution. Final answer round to the nearest whole numberConstruction cost for year 1 & 2 = $6 mil , $12 million totoal Operation and Maintenance (op. and main) Costs = 3rd yr (1st yr of operation) to 25th yr (last yr of operation). with nominal $800,000 in 3rd yr Annual electricity sales = year 3~25 , with nominal $850,000 in 3rd yr annual growth rate of the op. and main costs = 1%, annual growth rate of revenue = 3% social discount rate = 0.04 inflation = 0.02 terminal value = $23 mil. (nominal) 2) what is the IRR and NPV of the projectNet Present Value Analysis [L014-2] Oakmont Company has an opportunity to manufacture and sell a new product for a four-year period. The company's discount rate is 18%. After careful study, Oakmont estimated the following costs and revenues for the new product: \table[[Cost of equipment needed,$270,000
- The maintenance cost of a certain equipment is P80,000.00 per year for the first 5 years, P120,000.00 per year for the next 5 years, cost of overhaul at the end of the 5th year and the 8th year is P280,000.00. Find the equivalent uniform annual cost of maintenance if money is worth 6% compounded annually? Answer. P149,403.62Construction cost for year 1 & 2 = $6 mil , $12 million totoal Operation and Maintenance (op. and main) Costs = 3rd yr (1st yr of operation) to 25th yr (last yr of operation). with nominal $800,000 in 3rd yr Annual electricity sales = year 3~25 , with nominal $850,000 in 3rd yr annual growth rate of the op. and main costs = 1%, annual growth rate of revenue = 3% social discount rate = 0.04 inflation = 0.02 terminal value = $23 mil. (nominal) 4) under the original project life of 25 years, conduct a sensitivity analysis where the sales decrease by 10% and then go up by 10%CLTV Section A company secured a contract that will result in income payments received of $280,000 today, $400,000 in 2 years and $600,000 in 5 years (these are single or lump sum payments they get). The expenses or outflows will include payments of $10,000 at the beginning of every month for 6 years and a one-time payment (expense) of $50,000 in one year from today. If the cost of money is 17% compounded annually, determine the Net Present Value (NPV) of the contract. a)What is the PV of the inflows? b) What is the PV of the outflows? c) What is the Net Present Value (NPV)?
