Tutorial ExerciseFind the derivative of the function. Simplify and express the answer using positive exponents only.(x² – 2)3y =x2 + 3Step 1u(x)where u and v are differentiable functions of x, with v(x) + 0, thenv(x)Recall the Quotient Rule: If f(x)v(x) · u'(x) – u(x) • v'(x)f'(x) =2(x² – 2)3We can apply the Quotient Rule to find the derivative of y =if we let u(x) = (x² – 2)³ andx* + 3v(x) = x2 + 3.Begin by finding the derivative of v(x).If v(x) = x + 3, then v'(x) =

Name: Tutorial ExerciseFind the derivative of the function. Simplify and ex
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Description: Tutorial ExerciseFind the derivative of the function. Simplify and express the answer using positive exponents only.(x² – 2)3y =x2 + 3Step 1u(x)where u and v are differentiable functions of x, with v(x) + 0, thenv(x)Recall the Quotient Rule: If f(x)

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Math

Calculus

Find the derivative of the function. Simplify and express the answer using positive exponents only. (x² – 2)3 x2 + 3 y =

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)

6th Edition

ISBN:9781337111348

Author:Bruce Crauder, Benny Evans, Alan Noell

Publisher:Bruce Crauder, Benny Evans, Alan Noell

Chapter1: Functions

Section1.2: Functions Given By Tables

Problem 32SBE: Does a Limiting Value Occur? A rocket ship is flying away from Earth at a constant velocity, and it...

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Find the derivative of the function. Simplify and express the answer using positive exponents only. y = (x2 − 3)3 x2 + 3 Step 1 Recall the Quotient Rule: If f(x) = u(x) v(x) where u and v are differentiable functions of x, with v(x) ≠ 0, then f '(x) = v(x) · u'(x) − u(x) · v'(x) v(x) 2 . We can apply the Quotient Rule to find the derivative of y = (x2 − 3)3 x2 + 3 if we let u(x) = (x2 − 3)3 and v(x) = x2 + 3. Begin by finding the derivative of v(x). If v(x) = x2 + 3, then v'(x) =
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