Find the directional derivative of f(x, y) = sin(x + 2y) at the point (1, -3) in the direction 0 The gradient of ƒ is: Vf = ( cos(x+2y) T/3. 2cos(x+2y) Vf(1, –3) = ( cos(5) 2cos(5) The directional derivative is: sqrt(5)/2"cos(5)

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find the directional derivative of f(x, y)
The gradient of ƒ is:
sin(x + 2y) at the point (1, -3) in the direction 0 = T/3.
Vf =
cos(x+2y)
, 2cos(x+2y)
Vf(1, –3) = ( cos(5)
, 2cos(5)
The directional derivative is:
sqrt(5)/2*cos(5)
Transcribed Image Text:Find the directional derivative of f(x, y) The gradient of ƒ is: sin(x + 2y) at the point (1, -3) in the direction 0 = T/3. Vf = cos(x+2y) , 2cos(x+2y) Vf(1, –3) = ( cos(5) , 2cos(5) The directional derivative is: sqrt(5)/2*cos(5)
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