Find the equation for the line passing through P = (2, -2, 1) and perpendicular to the plane -x + y – 3z = 3. Note that the correct answer below can be either in parametric or symmetric form. О А. (2t, — 2t, t) о в. (2 + t, -2 - t,1 + 3t) x +1 y - 1 z+3 -2 1 y+2 %3D z - 1 -3 O E. -x + y – 3z = -6

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