Find the equation of the normal line of y = 8 – x³ at (-1 , -3) а. 8-Зу — х %3D 0 b. х— Зу — 8 %3D 0 C. -x + 3y + 10 = 0 d. x+ 3y = 10

Trigonometry (MindTap Course List)
10th Edition
ISBN:9781337278461
Author:Ron Larson
Publisher:Ron Larson
Chapter6: Topics In Analytic Geometry
Section6.2: Introduction To Conics: parabolas
Problem 4ECP: Find an equation of the tangent line to the parabola y=3x2 at the point 1,3.
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Question
31. Find the equation of the normal line of y =
8 – x³ at (-1 , -3)
Mes
а. 8-Зу — х %3D 0
b. х— Зу — 8%3D0
C. -x + 3y + 10 = 0
d. x+3y = 10
Transcribed Image Text:31. Find the equation of the normal line of y = 8 – x³ at (-1 , -3) Mes а. 8-Зу — х %3D 0 b. х— Зу — 8%3D0 C. -x + 3y + 10 = 0 d. x+3y = 10
32. Find the equation of the tangent line to the
curve y = 2x? + 3 that is parallel to the line
8x – y + 3 = 0
а. 8х — у — 5%3D0
b. 8x +y – 27 = 0
С. 8х + у — 5%3D0
d. 8x + y --= 0
nme
63
mm
Transcribed Image Text:32. Find the equation of the tangent line to the curve y = 2x? + 3 that is parallel to the line 8x – y + 3 = 0 а. 8х — у — 5%3D0 b. 8x +y – 27 = 0 С. 8х + у — 5%3D0 d. 8x + y --= 0 nme 63 mm
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