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Find the equation of the tangent line to the curve at a given point y=x3-3x+1 (3, 19)

Question

Find the equation of the tangent line to the curve at a given point 

y=x3-3x+1 (3, 19)

 

check_circleAnswer
Step 1

Given,

 

Curve is y x-3x +1 and the point is (3,19)
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Curve is y x-3x +1 and the point is (3,19)

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Step 2

Now the slope of the tangent is the derivative of the ...

dy
= 3x2-3
dx
dy
=3 (3)-3 24
dx
slope of the tangent
(3.19)
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Image Transcriptionclose

dy = 3x2-3 dx dy =3 (3)-3 24 dx slope of the tangent (3.19)

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Tagged in

Math

Calculus

Derivative

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