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Find the equation of the tangent line to the curve y = x^2 + sqrt(x) at a = 1.

Question

Find the equation of the tangent line to the curve y = x^2 + sqrt(x) at a = 1.

check_circleAnswer
Step 1

Given function is,

y x2x
Substitute 1 forx and obtain the value of y in the given equation,
y(i
- 1 +1
2
Thus, the line has a point (1,2)
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Image Transcriptionclose

y x2x Substitute 1 forx and obtain the value of y in the given equation, y(i - 1 +1 2 Thus, the line has a point (1,2)

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Step 2

The slope of the tangent at a...

y'(x +
1
=2x
2Vx
Now obtain slope m by substituting 1 for above derivative
m y (1)
1
- 2(1)
+
1
= 2 +
2
-2.5
help_outline

Image Transcriptionclose

y'(x + 1 =2x 2Vx Now obtain slope m by substituting 1 for above derivative m y (1) 1 - 2(1) + 1 = 2 + 2 -2.5

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Math

Calculus

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