Find the equation of the tangent line to the following curve at the indicated point.36 at (1,- 6)xy2у -Click if you would like to Show Work for this question:Open Show WorkSHOW HINTLINK TO TEXTBy accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your3.73.7StudyI 2000-2019 John Wiley & Sons, Inc. All Rights Reserved. A Division of John Wiley & Sons Inc.I Privacy Policy

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Asked Oct 15, 2019
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Find the equation of the tangent line to the following curve at the indicated point.
36 at (1,- 6)
xy2
у -
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Find the equation of the tangent line to the following curve at the indicated point. 36 at (1,- 6) xy2 у - Click if you would like to Show Work for this question: Open Show Work SHOW HINT LINK TO TEXT By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your 3.7 3.7 Study I 2000-2019 John Wiley & Sons, Inc. All Rights Reserved. A Division of John Wiley & Sons Inc. I Privacy Policy

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Expert Answer

Step 1

We have to find the slope using dy/dx

Differentiate both side of the given equation w.r.t. x.

Used product rule on the left side. 

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xy2-36 d d y?)= dx d -(36) dx -(x)y2+x dx dy y2+2xy =0 dx

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Step 2

For point (1,-6) use x=1 , y=-6

Plug the values in the differe...

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dy y2+2xy 0= dx dy (-6)+2(1)-6) dx 0= dy 36-12 dx 0= dy 12 36 dx dy =3 dx

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