Find the equation that solves the area of the surface3(y² + 2) ,obtained by rotating the curve x =1< y< 3, about the y-axis.A. S = (y² + 1)(y² + 2),/y² + 2 dyB. S = (y² + 2)(y² + 1)/y² + 1 dyC. S = (y² + 2)/1+y²(y² + 2) dyD. S = (y? + 2)/(y² + 1)(y² + 2) dy33 2n1 3r3 2n1 3-3 2n%3D3c3 2n%3D1 3

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Find the equation that solves the area of the surface obtained by rotating the curve x = (y² + 2)% , 1< y< 3, about the y-axis. A. S = f" (y² + 1)(y² + 2)/y² + 2 dy B. S = v² + 2)(y² + 1)/y² + 1 dy C. S = Lv² + 2) /1+ y²Cy² + 2) dy D. S = f(y² + 2)/y² + 1)(y² + 2) dy -3 27n 1 3 3 2n - 3 r3 2n 3 -3 2n 1 3

Find the equation that solves the area of the surface obtained by rotating the curve x = (y² + 2)% , 1< y< 3, about the y-axis. A. S = f" (y² + 1)(y² + 2)/y² + 2 dy B. S = v² + 2)(y² + 1)/y² + 1 dy C. S = Lv² + 2) /1+ y²Cy² + 2) dy D. S = f(y² + 2)/y² + 1)(y² + 2) dy -3 27n 1 3 3 2n - 3 r3 2n 3 -3 2n 1 3

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter11: Topics From Analytic Geometry

Section: Chapter Questions

Problem 18T

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