find the exact area of the surface obtained by rotating x=t^3,y=t^2, 0<t<1 about the x-axis.
y=t^2 so t= sqrt(y)
x=t^3= (sqrt(y))^3 = y^(3/2)
x=y^(3/2) (graphed this equation)
Use the surface area formula .
There plug x=t^3 and y=t^2 then simplify.
When t=0 , then u=4
When t=1 then u=1...
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