Find the formula for the Riemann sum obtained by dividing the interval [– 1, 0] into n equal subintervals and using the right endpoint for each cr. Then take the limit of these sums as n → ∞ to calculate the area under the curve f(x) = 822 + 8x° over [– 1, 0]. The area under the curve over [– 1, 0] is square units.
Find the formula for the Riemann sum obtained by dividing the interval [– 1, 0] into n equal subintervals and using the right endpoint for each cr. Then take the limit of these sums as n → ∞ to calculate the area under the curve f(x) = 822 + 8x° over [– 1, 0]. The area under the curve over [– 1, 0] is square units.
Chapter5: Polynomial And Rational Functions
Section5.1: Quardratic Functions
Problem 74SE: A soccer stadium holds 62,000 spectators. With aticket price of$11, the average attendance has...
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PLEASE PLEASE PLEASE answer both of the questions, and I will give you a thumbs up!
![Find the formula for the Riemann sum obtained by dividing the interval [– 1, 0] into n equal
subintervals and using the right endpoint for each cr. Then take the limit of these sums as n → ∞
to calculate the area under the curve f(x) = 822 + 8x° over [– 1, 0].
The area under the curve over [– 1, 0] is
square units.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7e35a049-eff7-4413-9b42-5778293854ef%2Fd2ad3f6d-6edb-42a8-a9a4-0bd18730b241%2Fai0gfbl_processed.png&w=3840&q=75)
Transcribed Image Text:Find the formula for the Riemann sum obtained by dividing the interval [– 1, 0] into n equal
subintervals and using the right endpoint for each cr. Then take the limit of these sums as n → ∞
to calculate the area under the curve f(x) = 822 + 8x° over [– 1, 0].
The area under the curve over [– 1, 0] is
square units.
Transcribed Image Text:A baseball team plays in a stadium that holds 46000 spectators. With the ticket price at $8 the
average attendence has been 19000. When the price dropped to $7, the average attendence rose to
23000. Assume that attendence is linearly related to ticket price.
What ticket price would maximize revenue?
$4
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