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Please find the general solution of 1 and 2. Thanks
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- Obtain general solution y¹ = cos²x cos yBased on the following:i: x ≥0ii: y ≥0iii: z ≥0iv: 0.5x + y + 0.2x ≥ 600v: 2.0x + 3y + z ≤ 2000 I am confused how one gets the following coordinate - 1#4#5: (0, 500, 500) ------------------------ When x = 0 (x greater than or equal to zero), we get our fourth and fifth equation as 0.5(0)+y+0.2z=600 2.0(0)+3y+z=2000 y+0.2z = 600 3y+z = 2000 solving these two equations for y and z we get y = 500 and z = 500, so the coordinates are (0, 500, 500) -------------------------------- What is the calculation behind (0, 500, 500)? Need the breakdown on how from y+0.2z = 600 and 3y+z = 2000, the coordinates (0, 500, 500) came. Thank you.Use one step of Euler’s method to approximate y(0.1 + π/4 ) if y′ = xsin(x + y) and y( π/4 ) = 0.
- How do I solve this Bernoulli equation using P(x), Q(x) and n as well as u(y)?Suppose that a fourth order equation has a solution y = 2e^4x x cos x. a) Find such an equation. b) Find the initial conditions that the given solution satisfiesI need help use variation of parameters to find a particular solution, given the solutions y1, y2 ofthe complementary equation.