Find the improper integral 6 4z2+1 dz 6 S- dz 3'arctan(2x) + C The definite integral can be calculated witin the following interval O 0,00-8>0 00, B>000, B<0 The definite integral on this interval The limit of definite integral, it B→ ∞o Bum fol, da = arctan (a) + C 1+2 beta

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.3: Trigonometric Functions Of Real Numbers
Problem 65E
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Find the improper integral
6
4z2+1
dz
6
S- dz 3'arctan(2x) + C
The definite integral can be calculated witin the following interval
O 10,00-1A>0
[0,8 B>0 O 10,8] B<0
The definite integral on this interval
The limit of definite integral, if B→ ∞o
all Jong dem arctan (a)+C
1+2²
beta
Transcribed Image Text:Find the improper integral 6 4z2+1 dz 6 S- dz 3'arctan(2x) + C The definite integral can be calculated witin the following interval O 10,00-1A>0 [0,8 B>0 O 10,8] B<0 The definite integral on this interval The limit of definite integral, if B→ ∞o all Jong dem arctan (a)+C 1+2² beta
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