Find the indefinite integral. 1- Step 1 1 1- 6x-x² dx

Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter9: Polynomial And Rational Functions
Section9.2: Remainder And Factor Theorems
Problem 53PS
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I need help with this problem with step 2 what is du equals to

Step 2
10
10 - (x + 3
Let u = x + 3 and a = 10. Differentiate u in terms of x, du =
Rewrite the integration in terms of u and a.
1
1
| VIVIO) ² = (x + 352 dx = / √2² - 1² du
√(√10)²-(x 3)²
-
3)²
1
10- (x+3)²
X
Transcribed Image Text:Step 2 10 10 - (x + 3 Let u = x + 3 and a = 10. Differentiate u in terms of x, du = Rewrite the integration in terms of u and a. 1 1 | VIVIO) ² = (x + 352 dx = / √2² - 1² du √(√10)²-(x 3)² - 3)² 1 10- (x+3)² X
Find the indefinite integral.
1
√ √₁ - 6x-x²
1
Step 1
dx
To find the indefinite integral
Step 2
1
/
dx, rewrite the terms involving x in the denominator in the form of a complete square.
1 - 6x - X²
1
√ √ ₁ = ² x - x ² αx = /
dx
1 - 6x
J
J
1
-(x² + 6x
-(-9 + 9
10
10
1)
1
10
dx
1
1 + 6x + x²)
-
− (9 + 6x + x²)
1
10 (x+3
dx
1
dx
3)²
dx
Let u = x + 3 and a = ✓10. Differentiate u in terms of x, du = √10- (x+3)²
Transcribed Image Text:Find the indefinite integral. 1 √ √₁ - 6x-x² 1 Step 1 dx To find the indefinite integral Step 2 1 / dx, rewrite the terms involving x in the denominator in the form of a complete square. 1 - 6x - X² 1 √ √ ₁ = ² x - x ² αx = / dx 1 - 6x J J 1 -(x² + 6x -(-9 + 9 10 10 1) 1 10 dx 1 1 + 6x + x²) - − (9 + 6x + x²) 1 10 (x+3 dx 1 dx 3)² dx Let u = x + 3 and a = ✓10. Differentiate u in terms of x, du = √10- (x+3)²
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