Find the indefinite integral. [16 Step 1 The integral The integral 16x arcsin(x) dx S 16x arcsin(x) dx can be solved by using the technique of integration by parts. 1 16x arcsin(x) dx is to be expressed in the form The formula for integration by parts is Judv= then dv = uv Choose u such that its derivative Since we choose to have u = 16 arcsin(x), Choose dv such that it should be easy to integrate dv = X uv x Luc dx. u dv. derivative is a function simpler than u. □) integrate du.

Calculus: Early Transcendentals
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Chapter1: Functions And Models
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I need help with step 3 of this problem I did 1 and 2 help me fill in the blanks of step 3

Find the indefinite integral.
[₁
Step 1
16x arcsin(x) dx
The integral
The integral
S
16x arcsin(x) dx can be solved by using the technique of integration by parts.
J
16x arcsin(x) dx is to be expressed in the form
The formula for integration by parts is
Judv=
then
dv = uv
Choose u such that its derivative
Since we choose to have
u = 16 arcsin(x),
Choose dv such that it should be easy to integrate
dv = X
・S(
7)
V
dx.
Judv.
derivative is a function simpler than u.
du.
integrate
Transcribed Image Text:Find the indefinite integral. [₁ Step 1 16x arcsin(x) dx The integral The integral S 16x arcsin(x) dx can be solved by using the technique of integration by parts. J 16x arcsin(x) dx is to be expressed in the form The formula for integration by parts is Judv= then dv = uv Choose u such that its derivative Since we choose to have u = 16 arcsin(x), Choose dv such that it should be easy to integrate dv = X ・S( 7) V dx. Judv. derivative is a function simpler than u. du. integrate
Step 2
So we have
u = 16 arcsin(x).
Differentiate with respect to x on both sides.
16
du =
1-x²
V =
Step 3
Now, dv = x dx. Integrate on both sides.
16
√1-x²
Submit Skip (you cannot come back)
dx
Transcribed Image Text:Step 2 So we have u = 16 arcsin(x). Differentiate with respect to x on both sides. 16 du = 1-x² V = Step 3 Now, dv = x dx. Integrate on both sides. 16 √1-x² Submit Skip (you cannot come back) dx
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