Find the initial length of rod if strain value is 0.0003 and change in length value 0.3 mm
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Q: Find the initial length of rod if strain value is 0.0003 and change in length value 0.3 mm
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Q: Find the initial length of rod if strain value is 0.0003 and change in length value 0.3 mm
A: In the given question The strain of the rod is given as ε = 0.0003 Change in length ?L = 0.3 mm We…
Q: Find the initial length of rod if strain value is 0.0003 and change in length value 0.3 mm
A: Given data, strain, ε = 0.0003 Change in the length value, ∆L = 0.3 mm to find, the initial length…
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- A tensile test was performed on a metal specimen having a circular cross section with a diameter 0. 510 inch. For each increment of load applied, the strain was directly determined by means of a strain gage attached to the specimen. The results are, shown in Table: 1.5.1. a. Prepare a table of stress and strain. b. Plot these data to obtain a stress-strain curve. Do not connect the data points; draw a best-fit straight line through them. c. Determine the modulus of elasticity as the slope of the best-fit line.The results of a tensile test are shown in Table 1.5.2. The test was performed on a metal specimen with a circular cross section. The diameter was 3 8 inch and the gage length (The length over which the elongation is measured) was 2 inches. a. Use the data in Table 1.5.2 to produce a table of stress and strain values. b. Plot the stress-strain data and draw a best-fit curve. c. Compute the, modulus of elasticity from the initial slope of the curve. d. Estimate the yield stress.Determine the average normal stress in each rod if T2=400∘F Calculate the new length of the aluminum segment.
- A 20-foot-long W8 x 67 is suspended from one end. If the modulus of elasticity is 29,000 ksi. Determine the following: a) what is the maximum tesile stress, b) What is the maximum normal strainFor the beam shown, determine the support reactions and draw the stress diagrams. shear and bending moment. EI is constant. The rigth answer is: VA = 1.3 kN (↑); HA = 0 kN; MA = 4.40 kN.m (clockwise); VB = 51.20 kN (↑). I don't know how to get these results, please show how, step by step.When an axial load is applied to the ends of the two-segment rod shown in Figure P2.1, the total elongation between joints A and C is 7.5 mm. The segment lengths are a = 1.2 m and b = 2.8 m. In segment (2), the normal strain is measured as 2,075 um/m. Determine:(a) the elongation of segment (2).(b) the normal strain in segment (1) of the rod. (Ans. to check: Normal strain (1) = 825uE
- A steel rod of length = 3m, diameter = 300 mm and modulus of elasticity = 200 GPa is inserted into an aluminum tube. The aluminum tube as length = 2999.95 mm, wall thickness of 20 mm and modulus of elasticity of 70 GPa. a.) Determine the deformation of each member due to axial compressive force P = 100 KN. b.) Determine the stress in each member. c.) Determine the axial strain if no gap exists.A bar 500mm long and 200 mm in diameter is elongated by 1.2mm under axial pull of 105kn calculate stress and modulus of elasticity of barDetermine the a.Stress at 167 kN loadin MPa b.Strain at 167 kN loadin mm/mm(expressed in scientific notation) c.Modulus of elasticityMPa d.Modulus of resiliencein N-mm/mm3 e.Modulus of toughnessin N-mm/mm3
- Bars (1) are made of a polyimide plastic that has an elastic modulus of 3.8 GPa. Bar (2) is a nylon material that has an elastic modulus of 0.9 GPa. Each bar has a cross-sectional area of 1050 mm2. Using L = 395 mm and Δ = 7.3 mm, what magnitude of load P will cause the normal stress in each bar to be the same value? [Answer: P = 67.0 kN]In the shown diagram below, the curved out bar has an axis that is circular (with mean radius r = 12in) and is subjected to the m horizontal forces P = 400lb at the two ends. The cross-section of the bar is a triangular shape with height h and thickness t. If the allowable tensile stress in the bar is 12,000 psi, and height h=1.2 in, what's the minimum thickness tmin that is required?Determine the axial force in members of the truss shown below using the method of consistent deformations. Express your answer in kips and use two decimal places. Note that if the axial force is compression consider negative sign in your final answer.