Question
Asked Mar 24, 2019
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Find the largest number δ such that if |x − 4| < δ, then |2x − 8| < ε, where ε = 0.1.
δ ≤ 1

Repeat and determine δ with ε = 0.01.
δ ≤ 2

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Expert Answer

Step 1

When ε=0.1 and δ≤1

Simplifying the absolute value inequality:

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Step 2

Checking the minimum and maximum values of x in the required inequality:

Hence, 0.05<δ≤1

Therefore, the largest value of δ is 1

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Step 3

When ε=0.01 and δ≤2

Simplify...

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