Find the laylar polynomials of orders = 0,1,2,3, and 4 about x = No, and then find the nth laylor polynomials, Plx)for the function in sigma notation for fx) - e"; Xo = In2 Choose the correct answer. O po(x)= 2", a*(x - In2) PI(X) = 2"|| + atx - In2)), pi(x) = 2" |1+ a(x - In2) + 21 a*(x - In2), a'c – In2) P(x) = 2" |1+ a(x - In2) + 2! 31 (x - In2), '(x – In2)', a*x - In2)* PA(x) = 2" |1 + aix - In2) + + 2! 3! 4! 2"x- In2y Px) = k! O po(x)= 2", PI(x)- 2"|1 + ax), P:(x) = 2" |I + ax + PN) = 2" |1 + ar + PAN) = 2"|I + ar+ 21 3! 2 P.(X) = k! O po(x) = 1, a(x - In2) Pix) = 1+ atx - In2), p1(x) = 1 + a(x - In2) + 2! a*(x - In2), '(x - In2) Ps(x) =1+ alx - In2) + 21 31 a*(x - In2), a'(x – In2), a*x - In2) PA(x) -1+ a(x - In2) + 2! 3! a(x- In2y P.(X)= O po(x) = 2", a*x + In2) P(X) = 2"|1 + atx + In2)), p:(x) = 2" |1 + a(x + In2) + 21 a*(x + In2), a'c + In2) Pi(x) = 2" |1 + a(x + In2) + 21 3!
Find the laylar polynomials of orders = 0,1,2,3, and 4 about x = No, and then find the nth laylor polynomials, Plx)for the function in sigma notation for fx) - e"; Xo = In2 Choose the correct answer. O po(x)= 2", a*(x - In2) PI(X) = 2"|| + atx - In2)), pi(x) = 2" |1+ a(x - In2) + 21 a*(x - In2), a'c – In2) P(x) = 2" |1+ a(x - In2) + 2! 31 (x - In2), '(x – In2)', a*x - In2)* PA(x) = 2" |1 + aix - In2) + + 2! 3! 4! 2"x- In2y Px) = k! O po(x)= 2", PI(x)- 2"|1 + ax), P:(x) = 2" |I + ax + PN) = 2" |1 + ar + PAN) = 2"|I + ar+ 21 3! 2 P.(X) = k! O po(x) = 1, a(x - In2) Pix) = 1+ atx - In2), p1(x) = 1 + a(x - In2) + 2! a*(x - In2), '(x - In2) Ps(x) =1+ alx - In2) + 21 31 a*(x - In2), a'(x – In2), a*x - In2) PA(x) -1+ a(x - In2) + 2! 3! a(x- In2y P.(X)= O po(x) = 2", a*x + In2) P(X) = 2"|1 + atx + In2)), p:(x) = 2" |1 + a(x + In2) + 21 a*(x + In2), a'c + In2) Pi(x) = 2" |1 + a(x + In2) + 21 3!
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter6: Vector Spaces
Section6.3: Change Of Basis
Problem 17EQ
Related questions
Question
![Find the Taylor polynomials of arders n = 0,1,2,3, and 4about = xo, and then find the nth Taylor polynomials, p,(x} for the
function in sigma notation for
fx) - e"; Xo - In2
Choose the correct answer.
O po(x) = 2",
a(x - In2)
PI(x) = 2"[1 + tx - In2)], P:(x) = 2" |1+ a(x – In2) +
2!
a(x - In2)
a'x - In2)"
+
P(x) = 2" |1+ a(x - In2) +
2!
3!
(x - In2), a'(x - In2), a*(x - In2)"
P4(x) = 2" 1+aix – In2) +
+
+
2!
3!
4!
2" a ix - In2y
Px) =
k!
O po(x) = 2,
PI(x) = 2"|1 + ax), P:(x) = 2°|1 + ar +
pi(N) = 2"|I + ar +
2!
3!
a', a'
PA(N) = 2"|! + ar +
2!
+
3!
P.(x) =
k!
O po(x) = 1,
a(x - In2)
Pi(x) = 1+ atx - In2), p1(x) -1+ a(x - In2) +
2!
a*(x – In2), a*(x - In2)
ps(x) = 1 + alx - In2) +
2!
3!
a*(x- In2), a*(x - In2)
a*(x - In2)
P4(x) =1+ a(x - In2) +
2!
3!
4!
at (x - In2y
P.(x) =
O po(x) = 2",
a*(x + In2)|
P1(x) = 2"[1 + tx + In2)], P:(x) = 2" |1+ a(x + In2) +
2!
a*(x + In2), a'(x + In2)]
P(x) = 2" |1+alx + In2) +
2!
3!
(x + In2), ar'(x + In2)', a*(x + In2)"
P4(x) = 2" |1 + alx + In2) +
+
2!
3!
4!
P.(x) = 5"a*(x + In2yt
k!
O po(x) = a',
P1(x) = a*[1 + atx - In2)), P:(x) = a1+ ax – In2) +
a(x - In2)
2!
a*(x – In2), a'(x - In2)"
Pr(x) = a1+ a(x – In2) +
2!
3!
(x - In2) a'(x- In2)', a*(x - In2)"
P4(x) = af1+ alx – In2) +
2!
3!
4!
ax - In2)
P.(x) =
k!
kmi](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb13d0290-f829-48ab-9d7e-6e1e17563f7e%2F9e0a3b34-75fa-47f6-83c4-04d98b02e3ae%2F7lw4uwq_processed.png&w=3840&q=75)
Transcribed Image Text:Find the Taylor polynomials of arders n = 0,1,2,3, and 4about = xo, and then find the nth Taylor polynomials, p,(x} for the
function in sigma notation for
fx) - e"; Xo - In2
Choose the correct answer.
O po(x) = 2",
a(x - In2)
PI(x) = 2"[1 + tx - In2)], P:(x) = 2" |1+ a(x – In2) +
2!
a(x - In2)
a'x - In2)"
+
P(x) = 2" |1+ a(x - In2) +
2!
3!
(x - In2), a'(x - In2), a*(x - In2)"
P4(x) = 2" 1+aix – In2) +
+
+
2!
3!
4!
2" a ix - In2y
Px) =
k!
O po(x) = 2,
PI(x) = 2"|1 + ax), P:(x) = 2°|1 + ar +
pi(N) = 2"|I + ar +
2!
3!
a', a'
PA(N) = 2"|! + ar +
2!
+
3!
P.(x) =
k!
O po(x) = 1,
a(x - In2)
Pi(x) = 1+ atx - In2), p1(x) -1+ a(x - In2) +
2!
a*(x – In2), a*(x - In2)
ps(x) = 1 + alx - In2) +
2!
3!
a*(x- In2), a*(x - In2)
a*(x - In2)
P4(x) =1+ a(x - In2) +
2!
3!
4!
at (x - In2y
P.(x) =
O po(x) = 2",
a*(x + In2)|
P1(x) = 2"[1 + tx + In2)], P:(x) = 2" |1+ a(x + In2) +
2!
a*(x + In2), a'(x + In2)]
P(x) = 2" |1+alx + In2) +
2!
3!
(x + In2), ar'(x + In2)', a*(x + In2)"
P4(x) = 2" |1 + alx + In2) +
+
2!
3!
4!
P.(x) = 5"a*(x + In2yt
k!
O po(x) = a',
P1(x) = a*[1 + atx - In2)), P:(x) = a1+ ax – In2) +
a(x - In2)
2!
a*(x – In2), a'(x - In2)"
Pr(x) = a1+ a(x – In2) +
2!
3!
(x - In2) a'(x- In2)', a*(x - In2)"
P4(x) = af1+ alx – In2) +
2!
3!
4!
ax - In2)
P.(x) =
k!
kmi
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