Find the length of the curve: a) y=x^(3/2) +8 on the interval[0,2] b) x=(y^5)/5+1/(12y^3) on the interval[2,4](integrate with respect to y)

Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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3.Find the length of the curve:

a) y=x^(3/2) +8 on the interval[0,2]

b) x=(y^5)/5+1/(12y^3) on the interval[2,4](integrate with respect to y)

3. Find the length of the curve:
a) y = x³/2 +8 on the interval[0,2]
b)x= = V². +
1
12y-3
on the interval[2,4](integrate with respect to y)
Transcribed Image Text:3. Find the length of the curve: a) y = x³/2 +8 on the interval[0,2] b)x= = V². + 1 12y-3 on the interval[2,4](integrate with respect to y)
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